AMC 10 · 2011 · #6

Grade 7 algebra
systems-of-equationslinear-equations-one-var convert-to-algebra ↑ Prerequisites: linear-equations-one-var
📏 Medium solution 💡 2 insights
Problem
Two scoring kinds contribute equal points and a third count is one more than another. Find that third count.

Pick an answer.

(A)
13
(B)
14
(C)
15
(D)
16
(E)
17
How to solve
Strategy Introduce a Variable

Everything is tied to the number of two-point shots: the free throws are one more than it, and the equal-points rule lets me write the three-point total without ever counting three-point shots. So I name that one number, turn each clue into an expression in dollars of points, and solve a single equation.

1STEP 1

Name the number of two-point shots

One letter names every count.

two-point points = 2t
2STEP 2

Use the equal-points rule for threes

Equal points means equal points, not equal shots.

three-point points = two-point points = 2t
3STEP 3

Write the free-throw points

The third contribution is one more than a count.

free-throw points = t + 1
4STEP 4

Add the parts to 61

The three add to a single equation.

2t + 2t + (t + 1) = 61 → 5t + 1 = 61
5STEP 5

Solve and read off the free throws

Solving gives 13, choice (A).

5t = 60 → t = 12 → t + 1 = 13
Answer
13
Check with t = 12: two-point shots give 24 points, three-point shots give the same 24 points (that is 8 three-point shots, a whole number), and 13 free throws give 13 points. The total is 24 + 24 + 13 = 61, matching the problem, and 13 is choice (A). The count of free throws being one more than the 12 two-point shots also checks out.
💡Key takeaway

Anchor everything to one unknown, use 'equal points' to reuse a value you already wrote, then add all the scoring to the total and solve.

  • Name the number of two-point shots
  • Use the equal-points rule for threes
  • Write the free-throw points
  • Add the parts to 61
  • Solve and read off the free throws