AMC 10 · 2011 · #19

Grade 8 number-theorygeometry-2d
slope-interceptcoordinate-geometryfraction-arithmetic optimization ↑ Prerequisites: slope-intercept
📏 Long solution 💡 4 insights
Problem
A line must miss every grid point over a range of inputs, for every slope in an interval. Find the largest endpoint.

Pick an answer.

(A)
$\frac{51}{101}$
(B)
$\frac{50}{99}$
(C)
$\frac{51}{100}$
(D)
$\frac{52}{101}$
(E)
$\frac{13}{25}$
How to solve
Strategy Extreme Principle

The whole question is a boundary hunt, so Tool #14 (Extreme Principle) is primary: the largest safe a is pinned by the single closest "bad" slope sitting just above 1/2. To even see those bad slopes, use Tool #16 (Change Focus) — instead of chasing lattice points, translate "line hits a lattice point" into "the slope equals a fraction k/x with x ≤ 100." Tool #4 (Introduce a Variable) names that fraction so we can measure how far above 1/2 it sits. Finally Tool #3 (Eliminate Possibilities) checks the five answer choices against the boundary we find, catching the even-denominator trap 51/100.

1STEP 1

Reframe as a slope-is-a-fraction question

Hitting a grid point makes the slope a fraction.

y = mx + 2 ∈ Z ⇔ mx ∈ Z ⇔ m = k/x
2STEP 2

Name the target value of a

The answer is the closest such fraction above the start.

a_max = min{ k/x > 1/2 : 1 ≤ x ≤ 100 }
3STEP 3

Gap above one-half for a fixed denominator

For each denominator the gap has a simple size.

k/x - 1/2 = (2k - x)/2x ≥ 1/2x
4STEP 4

Odd denominators get closest

Odd denominators come closest.

x odd → gap = 1/2x; x even → gap ≥ 1/x
5STEP 5

Push the denominator to its maximum

So push the denominator to its largest odd value.

50/99 - 1/2 = 1/198 < 1/100 = 51/100 - 1/2
6STEP 6

Confirm the boundary and the answer

That gives 50/99, choice (B).

a_max = 50/99 → (B)
Answer
50/99
All five choices cluster just above 1/2, which fits: the answer must be a fraction barely larger than 0.5. Numerically 50/99 ≈ 0.50505, and the only choice below it is 51/101 ≈ 0.50495 — a safe but sub-maximal value, exactly the kind of near-miss the problem plants. The tempting wrong answer 51/100 = 0.51 is the best even-denominator fraction; our parity step is precisely what rules it out, since the odd denominator 99 hugs 1/2 twice as tightly. The winning slope 50/99 does hit the lattice point (99, 99·50/99+2) = (99, 52), confirming it is genuinely the first obstacle.
💡Key takeaway

Turn "the line dodges all lattice points" into "the slope isn't any fraction k/x with x ≤ 100," then find the fraction that hugs 1/2 most tightly from above — an odd denominator wins, and x=99 gives 50/99.

  • Reframe as a slope-is-a-fraction question
  • Name the target value of a
  • Gap above one-half for a fixed denominator
  • Odd denominators get closest
  • Push the denominator to its maximum
  • Confirm the boundary and the answer