AMC 10 · 2011 · #2

Grade 6 arithmetic
mean-median-mode-rangelinear-equations-one-var work-backwards ↑ Prerequisites: mean-median-mode-range
📏 Medium solution 💡 2 insights
Problem
One more score must lift the average by a fixed amount. Find the smallest score that does it.

Pick an answer.

(A)
80
(B)
82
(C)
85
(D)
90
(E)
95
How to solve
Strategy Work Backwards

The goal is stated in terms of the final average, and we must recover a single missing score. Tool #11 (Work Backwards) runs the average formula in reverse: from the target average, find the total the six tests must reach, then subtract what she already has. Tool #7 (Identify Subproblems) splits the job into current-average, target-total, and needed-score. Tool #3 (Eliminate Possibilities) uses the answer choices to confirm that anything below 95 falls short.

1STEP 1

Find the current average

The current average is 77.

(90+80+70+60+85)/5=385/5=77
2STEP 2

Set the target average

The target average is 80.

77+3=80
3STEP 3

Work backwards to the six-test total

That fixes a new total over six tests.

80×6=480
4STEP 4

Subtract to find the needed score

Subtracting gives 95, choice (E).

480-385=95 → (E)
Answer
95
Check the winning score directly: with a 95, the six scores total 385+95=480, and 480÷6=80, which is exactly 77+3 — the average rose by 3. Try the next choice down, 90: the total is 475 and the average is 475÷6≈79.2, only about 2.2 points up, short of the goal. So 95 is genuinely the smallest score that works, confirming (E).
💡Key takeaway

To find one missing score for a target average, figure out the total all the tests must reach, then subtract the points you already have.

  • Find the current average
  • Set the target average
  • Work backwards to the six-test total
  • Subtract to find the needed score