AMC 10 · 2011 · #4

Grade 4 number-theory
prime-factorizationdigit-decompositionplace-value work-backwards ↑ Prerequisites: prime-factorization
📏 Medium solution 💡 2 insights
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Problem
A two-digit factor was written backwards, giving the wrong product. Find the true product.

Pick an answer.

(A)
116
(B)
161
(C)
204
(D)
214
(E)
224
How to solve
Strategy Work Backwards

The wrong product 161 is the end of Ron's mistake, and we need the numbers he started from, so Tool #11 (Work Backwards) fits: factor 161 to recover the two numbers he actually multiplied. Tool #3 (Eliminate Possibilities) then picks which factor is the reversed two-digit number — only one factor has two digits. Tool #7 (Identify Subproblems) breaks the rest into small steps: un-flip the digits to get a, then do the correct multiplication.

1STEP 1

Factor the wrong product

The wrong product splits into two primes.

161 = 7 × 23
2STEP 2

Pick the reversed two-digit factor

Only one of them has two digits.

reversed a = 23, b = 7
3STEP 3

Un-flip the digits to get a

Flipping its digits back recovers the true factor.

23 → a = 32
4STEP 4

Multiply correctly

Multiplying gives 224, choice (E).

a × b = 32 × 7 = 224 → (E)
Answer
224
Check the story both ways. Reversed a = 23 times b = 7 gives 23 × 7 = 161, exactly Ron's wrong product, so the factoring is right. The true a = 32 times b = 7 gives 224, which is close to but a bit larger than 161 — sensible, since 32 > 23. The answer 224 is choice (E), and the tempting 161 (choice B) is only the mistaken product, not the correct one.
💡Key takeaway

Break the wrong answer into its factors, flip the two-digit one back to the real number, then multiply again to get the true product.

  • Factor the wrong product
  • Pick the reversed two-digit factor
  • Un-flip the digits to get a
  • Multiply correctly