AMC 10 · 2011 · #6

Grade 10 geometry-2d
arc-measuretangent-circlesangle-sum-triangleratio-proportion identify-subproblems ↑ Prerequisites: arc-measure
📏 Long solution 💡 3 insights
Problem
Two tangent lines from an outside point split a circle into arcs of a known ratio. Find the angle between them.

Pick an answer.

(A)
24
(B)
30
(C)
36
(D)
48
(E)
60
How to solve
Strategy Draw a Diagram

The problem gives no lengths, only a ratio, so everything has to come out of the picture (Tool #1): draw the center O and the radii OB and OC, because the one fact that connects a tangent to the circle's center is that a tangent is perpendicular to the radius at the touch point. Tool #4 turns the ratio 2 : 3 into arc measures 2x and 3x that must sum to 360°. Tool #7 then breaks the figure into two right triangles OBA and OCA and chases angles inside them. Tool #14 handles the question the ratio quietly raises — whether the two tangents meet at all — by testing the boundary case where they would be parallel.

1STEP 1

Draw the center and the radii

The centre and two radii complete the picture.

Circle (O, r), B, C on the circle, AB, AC tangent
2STEP 2

Arc length ratio equals arc degree ratio

An arc length ratio is an angle ratio.

arc₁/arc₂ = (θ₁/360 · 2π r)/(θ₂/360 · 2π r) = θ₁/θ₂ = 2/3
3STEP 3

Split the full turn in ratio 2 to 3

Splitting a full turn gives 144 degrees at the centre.

2x + 3x = 360 → x = 72 → arcs = 144°, 216° → ∠ BOC = 144°
4STEP 4

Check the two tangents actually meet

The two tangents really do meet.

tangents parallel ⇔ arcs 1 : 1; 2 : 3 ≠ 1 : 1 → A exists and is unique
5STEP 5

Tangent meets radius at a right angle

Each tangent meets its radius at a right angle.

OB ⊥ AB, OC ⊥ AC → ∠ OBA = ∠ OCA = 90°
6STEP 6

The line to the center bisects the central angle

The line to the centre bisects the central angle.

△ OBA ≅ △ OCA (HL) → ∠ BOA = ∠ COA = 144°/2 = 72°
7STEP 7

Angle sum in one right triangle

One right triangle gives half the answer, 18 degrees.

∠ BAO = 180° - 90° - 72° = 18° = ∠ CAO
8STEP 8

Add the two halves at A

Doubling gives 36 degrees, choice (C).

∠ BAC = 2 · 18° = 36° = 180° - 144° → (C)
Answer
36
The derivation produced a general rule worth testing: ∠ BAC = 180° - (smaller arc). Push it to the extremes. If the arcs approach 1 : 1, the smaller arc approaches 180° and ∠ BAC approaches 0° — correct, because then the tangents are parallel and never meet. If B and C crowd together, the smaller arc approaches 0° and ∠ BAC approaches 180° — correct, because the two tangents nearly flatten into one line. A ratio of 2 : 3 is only mildly away from 1 : 1, so a modest angle like 36° is exactly what to expect; anything near 60° would be too big. The rule also separates the distractors cleanly: 60° needs arcs 120 : 240 = 1 : 2, 48° needs 132 : 228 = 11 : 19, 30° needs 150 : 210 = 5 : 7, and 24° needs 156 : 204 = 13 : 17. Only 36° produces the given 2 : 3, so (C) is the unique fit.
💡Key takeaway

Draw the radii to the two touch points: a tangent always meets its radius at a right angle, and once you know the two arcs are 144° and 216°, the angle between the tangents is just 180° minus the smaller arc, which is 36°.

  • Draw the center and the radii
  • Arc length ratio equals arc degree ratio
  • Split the full turn in ratio 2 to 3
  • Check the two tangents actually meet
  • Tangent meets radius at a right angle
  • The line to the center bisects the central angle
  • Angle sum in one right triangle
  • Add the two halves at A