AMC 10 · 2013 · #12

Grade 11 geometry-2d
angle-sum-trianglesequences-arithmeticlaw-of-cosinesquadratic-equations identify-subproblemsconvert-to-algebracasework ↑ Prerequisites: law-of-cosines
📏 Long solution 💡 3 insights
Problem
A triangle has two known sides and three angles that step evenly. Add the possible third sides in the requested form.

Pick an answer.

(A)
36
(B)
38
(C)
40
(D)
42
(E)
44
How to solve
Strategy Identify Subproblems

"Angles in arithmetic progression" sounds like a condition on three separate numbers, but the 180° angle sum collapses it to a single fact: one angle equals 60°. The collapse has to work in both directions, because we will search for triangles with a 60° angle and then claim they qualify. Once the condition is just one 60° angle, the only freedom left is which side that angle faces. That splits the problem into three law-of-cosines subproblems, one per side, and each is a short piece of algebra.

1STEP 1

Angle sum forces a 60 degree angle

The angle sum forces a 60 degree angle.

A+C=2B, A+B+C=180^° → 3B=180^° → B=60^°
2STEP 2

Check the reverse direction too

Any step size still gives an even progression.

60^°-d, 60^°, 60^°+d is an arithmetic progression for every d
3STEP 3

Split by which side faces 60 degrees

Which side faces it splits the work into three cases.

c²=a²+b²-2abcos 60^°=a²+b²-ab
4STEP 4

Case: 60 degrees faces x

The first case gives one root.

x²=4²+5²-4 · 5=21 → x=√(21)
5STEP 5

Case: 60 degrees faces the side 5

The second gives a quadratic.

5²=4²+x²-4x → x²-4x-9=0 → x=4±√(52)/2=2±√(13)
6STEP 6

Case: 60 degrees faces the side 4 fails

The third has no real solution at all.

4²=5²+x²-5x → x²-5x+9=0, Δ=25-36=-11 < 0
7STEP 7

Confirm both survivors are real triangles

Both survivors are genuine triangles.

x=√(21)≈ 4.58, x=2+√(13)≈ 5.61
8STEP 8

Add them and match the form

Matching the form gives 36, choice (D).

√(21)+(2+√(13))=2+√(13)+√(21), a+b+c=2+13+21=36
Answer
36
Test the two triangles against the original wording instead of against the method. For x = √(21) the sides are 4, √(21), 5 and the angles work out near 49.1°, 60°, 70.9°, with equal gaps of about 10.9°. For x = 2+√(13) the sides are 4, 5, 5.61 and the angles are near 43.8°, 60°, 76.2°, with equal gaps of about 16.2°. Both are honest arithmetic progressions, and in each the side facing 60° is the middle-length side, as it must be. The sum is about 4.58+5.61 = 10.19, matching 2+3.61+4.58, and a+b+c = 36 is choice (A).
💡Key takeaway

In a triangle, "the angles are evenly spaced" means nothing more and nothing less than "one angle is 60°" — and then the only question left is which side that angle faces.

  • Angle sum forces a 60 degree angle
  • Check the reverse direction too
  • Split by which side faces 60 degrees
  • Case: 60 degrees faces x
  • Case: 60 degrees faces the side 5
  • Case: 60 degrees faces the side 4 fails
  • Confirm both survivors are real triangles
  • Add them and match the form