AMC 10 · 2013 · #1

Grade 7 algebra
mean-median-mode-rangelinear-equations-one-var convert-to-algebra ↑ Prerequisites: linear-equations-one-var
📏 Medium solution 💡 1 insight
Problem
The gap between a high and a low is known, and so is their average. Find the low.

Pick an answer.

(A)
-13
(B)
-8
(C)
-5
(D)
-3
(E)
11
How to solve
Strategy Introduce a Variable

There is one unknown, the low temperature, and every other quantity is described in terms of it, so Tool #4 (Introduce a Variable) names the low as L and lets the high be written as L+16. Tool #13 (Convert to Algebra) then turns the sentence “the average is 3” into a single equation to solve. Tool #3 (Eliminate Possibilities) is a fast backstop: only one listed low pairs with a high that is 16 larger and averages 3.

1STEP 1

Name the low and write the high

One letter names both temperatures.

low=L, high=L+16
2STEP 2

Turn the average into an equation

The average becomes one equation.

(L+(L+16))/2=3
3STEP 3

Simplify the equation

Simplifying leaves the low plus 8.

(2L+16)/2=L+8=3
4STEP 4

Solve for the low temperature

Solving gives -5, choice (C).

L=3-8=-5 → (C)
Answer
-5
Test the low of -5: the high is -5+16=11, and the average is (-5+11)/2=6/2=3, which matches. The gap between high and low is 11-(-5)=16, also as required. Both facts hold, so (C) is correct. The answer should be below 3 (a low is colder than the average), which rules out (E) 11 immediately.
💡Key takeaway

The average of two numbers sits exactly halfway between them, so the low is the average minus half the gap.

  • Name the low and write the high
  • Turn the average into an equation
  • Simplify the equation
  • Solve for the low temperature