AMC 10 · 2013 · #6

Grade 8 algebra
completing-the-squareperfect-squares completing-the-square ↑ Prerequisites: perfect-squares
📏 Medium solution 💡 2 insights
Problem
One equation ties two real numbers together with squares on one side. Find their sum.

Pick an answer.

(A)
1
(B)
2
(C)
3
(D)
6
(E)
8
How to solve
Strategy Organize Information in More Ways

One equation with two unknowns usually cannot pin down each value, so a plain solve will not work. Instead, rearrange the equation and complete the square to rewrite it as a sum of squares. That new form is more useful: a sum of squares can only equal 0 when every square is 0, which forces exact values for x and y.

1STEP 1

Move all terms to one side

Everything moves to one side.

x² - 10x + y² + 6y + 34 = 0
2STEP 2

Complete the square for each variable

Each variable completes into a square.

x² - 10x = (x-5)² - 25, y² + 6y = (y+3)² - 9
3STEP 3

Combine the leftover numbers

The constants cancel to exactly zero.

(x-5)² - 25 + (y+3)² - 9 + 34 = 0 → (x-5)² + (y+3)² = 0
4STEP 4

Force each square to 0

Both squares vanish, giving 2, choice (E).

(x-5)² = 0, (y+3)² = 0 → x = 5, y = -3 → x + y = 2
Answer
2
Put x = 5 and y = -3 back into the original equation. The left side is 25 + 9 = 34. The right side is 10(5) - 6(-3) - 34 = 50 + 18 - 34 = 34. Both sides match, so the point (5, -3) is correct and x + y = 2, which is choice (B).
💡Key takeaway

Complete the square to turn the equation into a sum of squares equal to 0, then remember a sum of squares is 0 only when every square is 0.

  • Move all terms to one side
  • Complete the square for each variable
  • Combine the leftover numbers
  • Force each square to 0