AMC 10 · 2013 · #8

Grade 8 geometry-2d
coordinate-geometryarea-trianglessystems-of-equationsslope-intercept convert-to-algebraidentify-subproblems ↑ Prerequisites: coordinate-geometryarea-triangles
📏 Medium solution 💡 2 insights
Problem
Three lines through known points bound a triangle of given area. Find the third line's slope.

Pick an answer.

(A)
$\frac{2}{3}$
(B)
$\frac{3}{4}$
(C)
1
(D)
$\frac{4}{3}$
(E)
$\frac{3}{2}$
How to solve
Strategy Introduce a Variable

The only thing free to move is C, which slides along the horizontal line y = 1. Name its x-coordinate. Then the base BC is horizontal and the height from A is locked at a single number, so the area condition becomes one equation in one letter. That equation has two roots, so the last job is to decide honestly which one the positive-slope condition allows, and then check the survivor really produces area 3.

1STEP 1

Find B by substitution

Substitution finds the first crossing point.

3x - 2(1) = 1 ⟹ x = 1 ⟹ B = (1,1)
2STEP 2

Use the horizontal side as base

The horizontal side makes a clean base.

h = |1 - (-2)| = 3, [ABC] = 1/2 · BC · 3
3STEP 3

Solve for C's position

The area gives two candidate positions.

1/2 |c-1| · 3 = 3 ⟹ |c-1| = 2 ⟹ c = 3 or c = -1
4STEP 4

Rule out the vertical candidate

One would make the line vertical.

c = -1 ⟹ x_C = x_A = -1 ⟹ line x = -1, slope undefined
5STEP 5

Compute the slope and check it

The other gives slope 3/4, choice (C).

m = (1 - (-2))/(3 - (-1)) = 3/4 > 0, [ABC] = 1/2 · 2 · 3 = 3
Answer
3/4
Plot the three points: A = (-1,-2), B = (1,1), C = (3,1). The top side runs along y = 1 from x = 1 to x = 3, so it has length 2, and A sits 3 units below that line, giving area 1/2 · 2 · 3 = 3 as required. The slope 3/4 is positive and is choice (B). A steepness check agrees: l₁ has slope 3/2 and climbs from A to y = 1 in a horizontal run of 2; l₃ is flatter, so it needs a longer run, and indeed it takes a run of 4 to reach y = 1, landing at x = 3 to the right of B. Every answer choice is positive, so the choices themselves give no shortcut, which is a sign the case analysis genuinely had to be done.
💡Key takeaway

When one side of a triangle lies on a horizontal line, use that side as the base: the height stops changing, and the area then tells you exactly how long the base must be.

  • Find B by substitution
  • Use the horizontal side as base
  • Solve for C's position
  • Rule out the vertical candidate
  • Compute the slope and check it