AMC 10 · 2014 · #6

Grade 7 number-theoryalgebra
digit-decompositionplace-valuedigit-constraintslinear-equations-two-var convert-to-algebrabound-inequality-then-enumerate ↑ Prerequisites: place-valuedigit-decomposition
📏 Medium solution 💡 3 insights
Problem
A two-digit number and its reverse differ by a multiple of their digit sum. Find their total.

Pick an answer.

(A)
44
(B)
55
(C)
77
(D)
99
(E)
110
How to solve
Strategy Convert to Algebra

The words "reversing its digits" only become usable once the digits are separate objects, so Tool #4 names them a and b and Tool #13 turns place value into algebra: N = 10a+b and M = 10b+a. Every phrase in the problem then becomes an expression — the difference is 9(a-b), the digit sum is a+b, and the quantity asked for is 11(a+b). That reduces the whole puzzle to one linear equation. One equation with two unknowns is normally hopeless, so Tool #3 supplies the missing pressure: a and b are digits, so only whole numbers from a short list are allowed, and the equation 2a = 7b leaves exactly one of them standing. Tool #6 then does the part that is easy to skip — plugging the candidate back into the original sentence to confirm such a number really exists, rather than only that it would have to look this way. Tool #16 covers the wording gap by re-running the argument with the roles of the two numbers swapped.

1STEP 1

Name the digits

Two digits describe both numbers.

N = 10a + b, M = 10b + a, 1 ≤ a ≤ 9, 0 ≤ b ≤ 9
2STEP 2

Translate the sentence

The sentence becomes one clean equation.

N - M = (10a+b) - (10b+a) = 9(a-b), digit sum = a+b, so 9(a-b) = 5(a+b)
3STEP 3

Reduce to 2a = 7b

It reduces to a small ratio.

9a - 9b = 5a + 5b → 4a = 14b → 2a = 7b
4STEP 4

Force the digits

Divisibility forces both digits.

7 ∣ 2a and gcd(7,2) = 1 → 7 ∣ a → a ∈ {0, 7}; a ≠ 0, so a = 7, b = 2
5STEP 5

Check that it really works

Substituting back confirms it.

72 - 27 = 45 and 5(7+2) = 5 · 9 = 45, so the condition holds
6STEP 6

Handle the other orientation

The other orientation gives the same pair.

9(b-a) = 5(a+b) → 2b = 7a → b = 7, a = 2, i.e. the pair {27, 72} once more
7STEP 7

Answer the question asked

Their total is 99, choice (D).

N + M = (10a+b) + (10b+a) = 11(a+b) = 11 · 9 = 99 → (D)
Answer
99
Two independent structural facts back up 99. First, N + M = 11(a+b) must be a multiple of 11 — but that alone decides nothing here, since 44, 55, 77, 99 and 110 are all multiples of 11. The real filter is the equation 5(a+b) = 9(a-b): the left side is a multiple of 9, and because 5 and 9 share no factor, 9 must divide a+b. With 0 ≤ a+b ≤ 18 that leaves a+b = 9 or a+b = 18, giving a sum of 99 or 198. The case a+b = 18 forces a = b = 9, whose difference is 0 rather than 5 · 18 = 90, so it dies on the mathematics, not merely on being absent from the answer list. Checking the choices from the other direction agrees: choice (A) needs a+b = 4 and a-b = 20/9, choice (B) needs a-b = 25/9, choice (C) needs a-b = 35/9, choice (E) needs a+b=10 and a-b = 50/9 — none of them whole numbers — while (D) needs a-b = 5, which the digits 7 and 2 deliver. Note that an argument built only on eliminating answer choices would show at most "if such a number exists, the sum is 99"; the explicit number 72 is what shows one exists at all.
💡Key takeaway

Reversing a two-digit number only trades the tens and the ones, so the gap is always 9 times the digit difference and the total is always 11 times the digit sum — write those two facts down and the puzzle turns into one small equation.

  • Name the digits
  • Translate the sentence
  • Reduce to 2a = 7b
  • Force the digits
  • Check that it really works
  • Handle the other orientation
  • Answer the question asked