AMC 10 · 2014 · #4

Grade 8 algebrarate-ratio
systems-of-equationsratio-proportion convert-to-algebra ↑ Prerequisites: systems-of-equations
📏 Short solution 💡 2 insights
Problem
Two different baskets of the same two goods have totals in a known ratio. Find the price ratio.

Pick an answer.

(A)
$\frac{3}{2}$
(B)
$\frac{5}{3}$
(C)
$\frac{7}{4}$
(D)
2
(E)
$\frac{13}{4}$
How to solve
Strategy Introduce a Variable

The prices are unknown, so Tool #4 (Introduce a Variable) names a muffin m and a banana b and writes each shopper's total as an expression. Tool #13 (Convert to Algebra) turns the phrase "twice as much" into a single equation, which after collecting like terms gives the ratio m/b directly — the two prices cancel, so no dollar amount is needed. Tool #3 (Eliminate Possibilities) is a fast sanity filter: muffins clearly cost more than bananas here, so the ratio must be more than 1, and only a clean value like 5/3 fits the arithmetic.

1STEP 1

Name the prices and write each total

Two letters price both baskets.

Susie=4m+3b, Calvin=2m+16b
2STEP 2

Turn "twice as much" into an equation

The comparison becomes one equation.

2m+16b=2(4m+3b)=8m+6b
3STEP 3

Collect like terms and read off the ratio

Collecting terms gives 5/3, choice (B).

2m+16b=8m+6b → 10b=6m → m/b=10/6=5/3 → (B)
Answer
5/3
The answer should be more than 1 because Calvin swaps a muffin for lots of bananas (2 muffins vs Susie's 4) yet still pays double — that only works if muffins are worth clearly more than bananas. The ratio 5/3≈1.67 is comfortably above 1, and it is a tidy fraction, both signs it is right. Choice (D) 2 or (E) 13/4 would make muffins too expensive to fit 10b=6m.
💡Key takeaway

Name each unknown price with a letter, turn "twice as much" into an equation, then gather like terms — the prices cancel and the ratio falls right out.

  • Name the prices and write each total
  • Turn "twice as much" into an equation
  • Collect like terms and read off the ratio