AMC 10 · 2014 · #6

Grade 8 rate-ratio
percentagefraction-arithmeticratio-proportionlinear-equations-one-var convert-to-algebrawork-backwards ↑ Prerequisites: fraction-arithmeticpercentage
📏 Medium solution 💡 3 insights
Problem
Two people drink most of unequal servings, one hands some over, and they end up equal. Find the combined amount.

Pick an answer.

(A)
30
(B)
32
(C)
36
(D)
40
(E)
50
How to solve
Strategy Convert to Algebra

Every amount in the story is described relative to the regular size, so Tool #4 (Introduce a Variable) names that size r and Tool #13 (Convert to Algebra) turns each sentence into an expression in r. The efficient move is Tool #16 (Change Focus): instead of tracking two glasses, notice that the handover does not change the total, so the pair drinks 5/2r no matter what, and 'they drank the same amount' means each drank 5/4r. Tool #11 (Work Backwards) then reads off how big the handover has to be for that to happen, while Tool #7 (Identify Subproblems) computes how big the handover actually is, in two pieces: a third of Ann's leftover, then 2 more ounces. Two descriptions of one quantity give one linear equation. Tool #6 (Guess and Check) closes the argument by putting r back into the story and replaying it, which is what shows the answer is possible and not just forced.

1STEP 1

Name the regular size

One letter names both servings.

Ed = r, Ann = r + 1/2r = 3/2r
2STEP 2

Look at the total, not the glasses

Each person drinks exactly half the total.

total = r + 3/2r = 5/2r, each person = 5/4r
3STEP 3

How big must the handover be

That fixes how big the handover must be.

g = 5/4r - r = 1/4r, 2g = 3/2r - r = 1/2r
4STEP 4

How big the handover actually is

The story says how big it actually is.

Ann's leftover = 1/4·3/2r = 3/8r, g = 1/3·3/8r + 2 = 1/8r + 2
5STEP 5

One equation, one regular size

Setting them equal gives a serving of 16.

1/4r = 1/8r + 2 → 1/8r = 2 → r = 16
6STEP 6

Replay the story, then add up

Replaying the story gives 40, choice (D).

Ed = 12 + 8 = 20, Ann = 18 + 2 = 20, together = 16 + 24 = 40 → (D)
Answer
40
Two independent readings of the handover pin down the same value. The total-based reading needs it to be 1/4r; the story-based reading makes it 1/8r + 2; both together force r = 16, and the equation is linear with a nonzero coefficient, so there is no second candidate. The replay confirms the situation is actually possible rather than merely consistent: Ann holds 6 ounces and gives away 4, which she can afford, and both people land on 20 ounces. The numbers are also ordinary drink sizes — a 16-ounce regular and a 24-ounce large — and the total 40 sits comfortably among the choices. Scanning the other choices rules them out directly: the total is 5/2r, so (A) 30, (B) 32, (C) 36, (E) 50 would mean r = 12, 12.8, 14.4, 20, and for those the required handover 1/4r (namely 3, 3.2, 3.6, 5) never matches the story's 1/8r + 2 (namely 3.5, 3.6, 3.8, 4.5).
💡Key takeaway

Passing lemonade changes who drinks it but not how much there is, so the handover just has to close exactly half the gap between the two drinks.

  • Name the regular size
  • Look at the total, not the glasses
  • How big must the handover be
  • How big the handover actually is
  • One equation, one regular size
  • Replay the story, then add up