AMC 10 · 2015 · #10

Grade 7 algebranumber-theory
factorsprime-factorizationpolynomial-factoring simons-favorite-factoring-tricksystematic-enumeration ↑ Prerequisites: factorspolynomial-factoring
📏 Medium solution 💡 2 insights
Problem
Two positive whole numbers satisfy one equation mixing their sum and their product. Find the larger one.

Pick an answer.

(A)
8
(B)
10
(C)
15
(D)
18
(E)
26
How to solve
Strategy Organize Information in More Ways

As written, x+y+xy=80 is a sum, and a sum of 80 can be split in a huge number of ways — there is nothing to grab. Tool #15 (Organize Information in More Ways) rewrites the same equation as a single product, because products of integers are rigid: a fixed product can only be built from that number's divisors. Tool #2 (Make a Systematic List) then lays out every divisor pair, and Tool #3 (Eliminate Possibilities) uses x > y > 0 to delete all of them but one. The whole solution turns on one thing worth being careful about: the divisor argument is only legal because both factors are proved to be positive integers.

1STEP 1

Add 1 to force a product

Adding one makes the left side a product.

x+y+xy=80 ⇔ x+y+xy+1=81 ⇔ (x+1)(y+1)=81
2STEP 2

Check the factors are positive integers

Both factors are whole and at least two.

y ≥ 1 → y+1 ≥ 2; x ≥ 2 → x+1 ≥ 3
3STEP 3

List every divisor pair of 81

There are only three divisor pairs.

81=3⁴; divisors {1,3,9,27,81}; 81=1 × 81=3 × 27=9 × 9
4STEP 4

Use x > y > 0 to delete pairs

The ordering leaves exactly one.

(x+1)(y+1)=81, x+1 > y+1 ≥ 2 → x+1=27, y+1=3
5STEP 5

Read off and verify x

Reading it off gives 26, choice (E).

x=26, y=2: 26+2+26 · 2=80 → (E)
Answer
26
Substituting back is decisive: 26+2+26 · 2=80 and 26 > 2 > 0, so (E) genuinely satisfies every condition. The other choices die fast, because x+1 must divide 81: the choices give x+1=9,11,16,19,27, and of these only 9 and 27 divide 81. The value x+1=9 forces y+1=9, i.e. x=y=8, which is exactly why 8 was offered as choice (A) — it satisfies the equation but not the strict inequality x > y. A rough size check agrees too: the larger factor of a pair multiplying to 81 must exceed √(81)=9, so x > 8, which rules out (A) before any arithmetic.
💡Key takeaway

When an equation mixes a sum and a product of two unknowns, add 1 to both sides and see whether it collapses into a single product — a product of positive integers can only happen in a handful of ways.

  • Add 1 to force a product
  • Check the factors are positive integers
  • List every divisor pair of 81
  • Use x > y > 0 to delete pairs
  • Read off and verify x