AMC 10 · 2015 · #20

Grade 11 geometry-2d
isosceles-trianglearea-trianglesherons-formulapolynomial-roots convert-to-algebrapolynomial-factoringestimation ↑ Prerequisites: isosceles-trianglearea-triangles
📏 Long solution 💡 4 insights
Problem
A second triangle matches the first in both perimeter and area but is not the same. Find the nearest whole number to its base.

Pick an answer.

(A)
3
(B)
4
(C)
5
(D)
6
(E)
8
How to solve
Strategy Introduce a Variable

T' looks like it has two unknowns, a and b, but the fixed perimeter ties them together, so the base b alone decides the triangle. Writing the area in terms of b turns "same area" into a single equation in a single unknown. That equation is a cubic, which sounds bad until you notice that T itself is a member of the same family and therefore already solves it — dividing out the solution you were handed leaves a quadratic. A final size estimate of the square root decides which listed number is nearest.

1STEP 1

Measure the triangle you were given

The given triangle's area and perimeter are easy.

h=√(5²-4²)=3, [T]=1/2 · 8 · 3=12, P=18
2STEP 2

Trade two unknowns for one

The perimeter trades two unknowns for one.

2a+b=18 ⟹ a=9-b/2
3STEP 3

Write the area using b only

The area is then a function of the base.

h²=(9-b/2)²-b²/4=81-9b, [T']=3b/2√(9-b), 0 < b < 9
4STEP 4

Turn equal areas into a cubic

Equal areas give one cubic.

b√(9-b)=8 ⟹ b²(9-b)=64 ⟹ b³-9b²+64=0
5STEP 5

The given triangle is already a root

The given triangle factors straight out.

b³-9b²+64=(b-8)(b²-b-8)
6STEP 6

Solve the leftover quadratic

The leftover quadratic gives the new base.

b²-b-8=0 ⟹ b=1±√(33)/2, b=(1+√(33))/2
7STEP 7

Check a real triangle exists

That triangle really exists.

b≈ 3.372, a≈ 7.314, b < 2a, P=18, [T']=12, b ≠ 8
8STEP 8

Decide between 3 and 4

Bounding the root gives 3, choice (A).

25 < 33 < 36 ⟹ 5 < √(33) < 6 ⟹ 3 < (1+√(33))/2 < 3.5
Answer
3
The triangle produced has sides about 7.314, 7.314, 3.372. Its perimeter is 2a + b = 18 by construction, and its area evaluates to 12.000, matching T on both counts, while its shape is clearly different: T is short and wide, T' is tall and narrow. Both are legitimate triangles with the same perimeter and area, which is exactly the situation the problem claims. The base 3.372 lies between 3 and 3.5, so choice (A) is nearest. Choice (E) 8 is the trap for anyone who forgets that T and T' must not be congruent, since 8 is just T described again.
💡Key takeaway

Fixing the perimeter leaves the base as the only free number, and the triangle you were handed already solves the resulting equation, so dividing it out hands you the other one.

  • Measure the triangle you were given
  • Trade two unknowns for one
  • Write the area using b only
  • Turn equal areas into a cubic
  • The given triangle is already a root
  • Solve the leftover quadratic
  • Check a real triangle exists
  • Decide between 3 and 4