AMC 10 · 2015 · #11

Grade 8 geometry-2d
coordinate-geometryarea-trianglesinteger-pythagorean-triples identify-subproblems ↑ Prerequisites: area-trianglescoordinate-geometry
📏 Medium solution 💡 3 insights
Problem
A line and the two axes enclose a triangle. Add its three altitudes.

Pick an answer.

(A)
20
(B)
$\dfrac{360}{17}$
(C)
$\dfrac{107}{5}$
(D)
$\dfrac{43}{2}$
(E)
$\dfrac{281}{13}$
How to solve
Strategy Draw a Diagram

The problem is about a line and the axes, so tool #1 (Draw a Diagram) comes first: plotting the intercepts pins down the three corners and reveals a right triangle resting against the axes. Once the shape is a right triangle with legs on the axes, the three altitudes split into easy pieces, so tool #7 (Identify Subproblems) handles them one at a time — the two legs are themselves altitudes, and the third altitude (to the slanted hypotenuse) comes from the area. Tool #3 (Eliminate Possibilities) is a safety net: only one answer choice has a denominator of 13, which is exactly what the hypotenuse altitude forces.

1STEP 1

Find the three corners

The intercepts give the three corners.

y=0→ x=5; x=0→ y=12; corners: (0,0),(5,0),(0,12)
2STEP 2

See the right triangle and its hypotenuse

It is a familiar right triangle with hypotenuse 13.

√(5²+12²)=√(25+144)=√(169)=13
3STEP 3

Two altitudes are the legs themselves

Two altitudes are the legs themselves.

h₁=12, h₂=5
4STEP 4

Third altitude from the area

The area gives the third altitude.

1/2·13 · h₃=30 → h₃=60/13
5STEP 5

Add the three altitudes

Adding gives 281/13, choice (E).

5+12+60/13=(221+60)/13=281/13
Answer
281/13
Check the size: the three altitudes are 12, 5, and 60/13≈4.6, so the sum is about 21.6. The fraction 281/13≈21.6 agrees. It also makes sense that the altitude to the long hypotenuse (≈4.6) is the shortest of the three, since the longest side needs the shortest height to keep the area at 30.
💡Key takeaway

In a right triangle the two legs are already altitudes; for the slanted side, use the fact that the area stays the same to find its matching height.

  • Find the three corners
  • See the right triangle and its hypotenuse
  • Two altitudes are the legs themselves
  • Third altitude from the area
  • Add the three altitudes