AMC 10 · 2015 · #23

Grade 7 geometry-3d
volume-rectangular-prismsurface-arealinear-diophantine bound-inequality-then-enumerate ↑ Prerequisites: surface-areavolume-rectangular-prism
📏 Long solution 💡 4 insights
Problem
A box's volume equals its surface area as a plain number, with whole-number edges. Count the boxes.

Pick an answer.

(A)
4
(B)
10
(C)
12
(D)
21
(E)
26
How to solve
Strategy Make a Systematic List

The question asks "how many", so the goal is a complete, no-overlap count (Tool #2, Make a Systematic List). To make the list finite, first translate volume and surface area into the equation abc=2(ab+bc+ca) and divide to get frac1a+frac1b+frac1c=1/2 (Tool #4, Introduce a Variable). The Extreme Principle (Tool #14) then traps the smallest edge a in a tiny range {3,4,5,6}, and each value of a becomes a separate subproblem (Tool #7) solved by listing factor pairs.

1STEP 1

Write the volume

Setting them equal gives one equation.

V = abc
2STEP 2

Write the surface area and equate

Dividing makes it a sum of reciprocals.

abc = 2(ab+bc+ca)
3STEP 3

Divide by abc

That bounds the smallest edge tightly.

1 = 2(1/c+1/a+1/b) → 1/a+1/b+1/c=1/2
4STEP 4

Bound the smallest edge a

Only four values are possible for it.

1/2 ≤ 3/a → a ≤ 6, 1/a < 1/2 → a ≥ 3
5STEP 5

Case a = 3

The first case factors into five boxes.

1/b+1/c=1/6 → (b-6)(c-6)=36
6STEP 6

Case a = 4

The second gives three more.

1/b+1/c=1/4 → (b-4)(c-4)=16
7STEP 7

Case a = 5

The third gives one.

1/b+1/c=3/10 → (b,c)=(5,10)
8STEP 8

Case a = 6

The last gives one too.

1/b+1/c=1/3 → (b,c)=(6,6)
9STEP 9

Add the cases

Adding gives 10, choice (B).

5 + 3 + 1 + 1 = 10 → (B)
Answer
10
10 is one of the listed choices. The cube (6,6,6) checks out directly: its volume is 216 and its surface area is 6 · 6² = 216, equal as required. The smallest edge a stayed inside {3,4,5,6}, so no case was skipped, and the counts 5,3,1,1 all came from complete factor-pair lists. The total 10 matches choice (B).
💡Key takeaway

Turn "volume equals surface area" into frac1a+frac1b+frac1c=1/2, squeeze the smallest edge into a few values, then count factor pairs in each case.

  • Write the volume
  • Write the surface area and equate
  • Divide by abc
  • Bound the smallest edge a
  • Case a = 3
  • Case a = 4
  • Case a = 5
  • Case a = 6
  • Add the cases