AMC 10 · 2015 · #25

Grade 11 geometry-2dpattern
vector-additionperiodic-functionthirty-sixty-ninety-trianglepythagorean-theorem pattern-recognitionwork-backwards ↑ Prerequisites: vector-additionpythagorean-theorem
📏 Long solution 💡 4 insights
Problem
Each hop is one unit longer and turns a fixed angle further than the last. Report the parts of the final distance.

Pick an answer.

(A)
2016
(B)
2024
(C)
2032
(D)
2040
(E)
2048
How to solve
Strategy Look for a Pattern

Adding 2015 hops one at a time is hopeless, and the hops never repeat because the lengths keep growing. But the directions do repeat: 12 × 30^°=360^°, so only twelve headings ever occur. Tool #1 (Draw a Diagram) puts those twelve headings on one picture and shows the deeper fact — headings six apart point exactly opposite, so all twelve add to zero. Tool #4 (Introduce a Variable) names the twelve unit headings u₀,…,u₁₁ so a hop becomes (length) × u_j and the whole trip becomes one sum. Tool #5 (Look for a Pattern) is the crux: chop the hops into blocks of twelve. Inside a block the lengths look like (block start)+j, and the (block start) part is multiplied by the sum of all twelve headings — which is zero. So every block of twelve hops moves the bee by exactly the same vector, however far out the spiral has grown. That converts 2015 hops into 168 copies of one short push. Tool #11 (Work Backwards) handles the awkward fact that 2015 is not a multiple of 12: overshoot to P₂₀₁₆ (which is 168 clean blocks) and then undo the single hop that went too far. Tool #15 (Organize Information in More Ways) does the bookkeeping that turns the twelve-hop push into exact coordinates by re-pairing the terms.

1STEP 1

Number the hops

Each hop is a length times a heading.

P₂₀₁₅=Σ_k=1²⁰¹⁵k u_k-1=Σ_m=0²⁰¹⁴(m+1) u_m, u_m=(cos 30m^°, sin 30m^°)
2STEP 2

Twelve headings, in opposite pairs

There are only twelve headings, in opposite pairs.

u_m+12=u_m, u_m+6=-u_m, Σ_m=0¹¹u_m=Σ_m=0⁵(u_m+u_m+6)=Σ_m=0⁵(u_m-u_m)=mathbf 0
3STEP 3

Every twelve hops gives the same push

Every block of twelve gives the same push.

B_m=Σ_j=0¹¹(12m+1+j) u_j=(12m+1)Σ_j=0¹¹u_j_= mathbf 0+Σ_j=0¹¹j u_j_= C=C for every m
4STEP 4

Measure that push exactly

That push is measured exactly.

Σ_j=0⁵u_j=(1, 2+√3) ⟹ C=-6(1, 2+√3)=(-6, -12-6√3)
5STEP 5

Ride 168 blocks to P₂₀₁₆

Riding whole blocks reaches a round landing.

P₂₀₁₆=168 C=168(-6, -12-6√3)=(-1008, -2016-1008√3)
6STEP 6

Undo the extra hop

Undoing one extra hop corrects it.

P₂₀₁₅=P₂₀₁₆-(1008√3, -1008)=(-1008-1008√3, -1008-1008√3)
7STEP 7

Distance back to the start

The two coordinates come out equal.

|P₀P₂₀₁₅|=√(t²+t²)=|t|√2=1008(1+√3)√2
8STEP 8

Match the required form

Matching the form gives 2024, choice (A).

1008(1+√3)√2=1008√2+1008√6 ⟹ a+b+c+d=1008+2+1008+6=2024
Answer
2024
Size check first. One twelve-hop block moves the bee |C|=6|(1,2+√3)|=6√(1+(2+√3)²)=6√(8+4√3)=12√(2+√3)=6(√6+√2)≈ 23.18 inches, using 2+√3=((√6+√2)/2)². With 168 such pushes that is about 168 × 23.18≈ 3894.6 inches, and the claimed answer 1008√2+1008√6≈ 1425.2+2468.9≈ 3894.6 agrees. Note this also says |P₂₀₁₆|=168|C|=1008(√6+√2)=|P₂₀₁₅| — P₂₀₁₅ and P₂₀₁₆ are the same distance from home, a coincidence that falls out of both routes and would be very unlikely to survive an arithmetic slip. A direct machine sum of all 2015 arrows gives (-2753.90721403, -2753.90721403) against the derived -1008(1+√3)=-2753.90721403, matching to ten digits in both coordinates. Structural check on the choices: the derivation forces a=c and a+c=2016, which is 2015+1 — the answer is 2016+b+d, and only the square-free pair {2,6} appears, giving 2024; the neighbouring options 2016, 2032, 2040, 2048 correspond to the tempting slips of dropping the radicands, of using 2016 hops instead of 2015, or of mis-simplifying √(2-√3). Finally the answer is far smaller than the total distance flown, 1+2+…+2015=2,031,120 inches, which is exactly right for a tight spiral whose net drift grows only linearly.
💡Key takeaway

Twelve turns of 30^° bring the heading right back to the start, so cut the 2015 hops into blocks of twelve — the growing lengths cancel, every block pushes the bee the same short distance, and 168 identical pushes are easy to add.

  • Number the hops
  • Twelve headings, in opposite pairs
  • Every twelve hops gives the same push
  • Measure that push exactly
  • Ride 168 blocks to P₂₀₁₆
  • Undo the extra hop
  • Distance back to the start
  • Match the required form