AMC 10 · 2016 · #14

Grade 8 algebra
sequences-geometricoptimizationquadratic-equations convert-to-algebra ↑ Prerequisites: sequences-geometric
📏 Medium solution 💡 3 insights
Problem
An endless geometric sum is positive and its second term is fixed. Find the smallest possible total.

Pick an answer.

(A)
$\frac{1+\sqrt{5}}{2}$
(B)
2
(C)
$\sqrt{5}$
(D)
3
(E)
4
How to solve
Strategy Extreme Principle

The question asks for a smallest possible value, which is a minimization problem, so the Extreme Principle leads. To use it, name the first term and ratio as variables, turn the two facts into algebra, and write S as a single expression in r. Then S is smallest exactly when one denominator quantity is largest, and that maximum is easy to find.

1STEP 1

Write the sum with a and r

Two letters describe the whole series.

S = a/(1-r), |r| < 1
2STEP 2

Use the second term to cut a variable

The second term removes one of them.

a r = 1 → a = 1/r, S = (1/r)/(1-r) = 1/(r - r²)
3STEP 3

Smallest S means largest denominator

The smallest total needs the largest denominator.

S = 1/(r - r²) is smallest when r - r² is largest, 0 < r < 1
4STEP 4

Maximize the denominator

Completing the square gives 4, choice (E).

r - r² = 1/4 - (r - 1/2)² ≤ 1/4 → S ≥ 1/1/4 = 4
Answer
4
Plug r = 1/2 back in: first term a = 1/r = 2, second term = 2 * 1/2 = 1 as required, and the sum is 2/(1 - 1/2) = 4. Any other allowed r between 0 and 1 makes r - r² smaller than 1/4, which makes S larger than 4, so 4 is genuinely the minimum and matches answer (E).
💡Key takeaway

To make a fraction as small as possible, make its bottom as big as possible.

  • Write the sum with a and r
  • Use the second term to cut a variable
  • Smallest S means largest denominator
  • Maximize the denominator