AMC 10 · 2017 · #8
Grade 9 algebraPick an answer.
No lengths are given, and none can be found: doubling every length leaves the condition unchanged. So chasing a and b separately is chasing something that does not exist. The fix is to name the quantity the problem actually asks for, k = (a/b)², and force the whole equation to be about k alone. That works because after using the Pythagorean theorem every term in the equation is a product of four length factors, so dividing through by b⁴ leaves pure ratios and no leftover units. What comes out is a single quadratic in k, and a quick sign check picks the one root a squared ratio is allowed to be.
Name the sides, find the diagonal
The diagonal follows directly from the two sides.
The diagonal is not a new mystery length; a rectangle's right angle turns it into the hypotenuse of a triangle you already know both legs of.
A rectangle's right angle turns the diagonal into the hypotenuse of a triangle whose legs are already known.
▸ Why?
In that right triangle the square on the diagonal equals the two squares on the sides added together.
▸ Why?
Every length carries the same scale factor, so the ratio the question asks about is free of size.
Write the ratio sentence as an equation
The equal-ratio sentence becomes one equation.
Two equal fractions become one clean product line the moment you cross-multiply, and the square root only names something you already have.
9.A-CED.A.2Convert To AlgebraMake the answer the unknown
Making the target the unknown turns it quadratic.
When every term carries the same number of length factors, dividing by one of them erases the sizes and leaves the shape, which is the only thing the problem ever fixed.
9.A-SSE.A.2Introduce A VariableSolve and keep the possible root
Dropping the negative root leaves the golden ratio's reciprocal.
Algebra hands back both roots of the quadratic, but only one of them can be the square of a real length ratio.
9.A-REI.B.4Eliminate PossibilitiesWhen a problem only fixes a shape and not a size, name the ratio it asks for as one letter and divide the whole equation by a matching power of one side; the lengths cancel and a single equation is left.
- Name the sides, find the diagonal
- Write the ratio sentence as an equation
- Make the answer the unknown
- Solve and keep the possible root