AMC 10 · 2018 · #14

Grade 11 algebra
logarithm-propertiesexponentspolynomial-rootsdomain-restrictionfraction-arithmetic convert-to-algebraidentify-subproblems ↑ Prerequisites: logarithm-propertiesexponents
📏 Medium solution 💡 3 insights
Problem
One positive number makes two logarithms equal: the logarithm of four in base three x, and the logarithm of eight in base two x. That number turns out to be a fraction in lowest terms. Find the sum of its numerator and denominator.

Pick an answer.

(A)
5
(B)
13
(C)
17
(D)
31
(E)
35
How to solve
Strategy Introduce a Variable

The equation is awkward because x hides inside two different bases, and there is no rule for comparing a base-3x logarithm with a base-2x logarithm directly. The fix is to name the quantity the two sides share. Call the common value y. Each logarithm statement then becomes an ordinary exponential statement, (3x)^y = 4 and (2x)^y = 8, with x back in a normal position. From there the two right-hand sides can be pushed to a common number, the exponent y cancels, and what is left is a plain polynomial equation in x.

1STEP 1

Name the shared value and drop the logs

Naming the shared value strips the logarithms.

Let y = log₃x 4 = log₂x 8 ⟹ (3x)^y = 4, (2x)^y = 8
2STEP 2

Push both right sides to the same number

Push both right sides to the same number.

[(3x)^y]³ = 4³ = 64, [(2x)^y]² = 8² = 64 ⟹ (3x)³y = (2x)²y
3STEP 3

Cancel the exponent y

Then the exponent cancels.

[(3x)³]^y = [(2x)²]^y ⟹ (3x)³ = (2x)²
4STEP 4

Solve the polynomial equation

Solve the leftover polynomial.

27x³ = 4x² ⟹ x²(27x - 4) = 0 ⟹ x = 0 or x = 4/27
5STEP 5

Check the domain and add p and q

Checking the domain and adding gives 31.

3x = 4/9 ≠ 1, 2x = 8/27 ≠ 1, gcd(4, 27) = 1 ⟹ p + q = 4 + 27 = 31
Answer
31
Substitute x = 4/27 back into the equation that the logarithms produced: (3x)³ = (4/9)³ = 64/729 and (2x)² = (8/27)² = 64/729, so the two sides match exactly. Checking the original logarithms directly is just as clean: 4/9 = (2/3)² and 4 = 2², so log₄/9 4 = log₂/3 2; likewise 8/27 = (2/3)³ and 8 = 2³, so log₈/27 8 = log₂/3 2 as well. Both sides equal the same number, roughly -1.71. A negative common value is expected, since each base is smaller than 1 while each argument is bigger than 1. Finally 4/27 is a fraction in lowest terms with p + q = 31, which is one of the listed choices.
💡Key takeaway

When an unknown is stuck inside a logarithm base, name the exponent the two sides share — the logarithms turn into ordinary powers, and the shared exponent cancels itself out.

  • Name the shared value and drop the logs
  • Push both right sides to the same number
  • Cancel the exponent y
  • Solve the polynomial equation
  • Check the domain and add p and q