AMC 10 · 2020 · #5

Grade 8 algebra
ratio-proportionlinear-equations-one-varfraction-arithmetic convert-to-algebraidentify-subproblems ↑ Prerequisites: ratio-proportionlinear-equations-one-var
📏 Short solution 💡 2 insights
Problem
Two teams play in a league where every game gives one team a win and the other a loss. The first team won two thirds of its games and the second won five eighths of its games. The second has 7 more wins and 7 more losses than the first. Find how many games the first team played.

Pick an answer.

(A)
21
(B)
27
(C)
42
(D)
48
(E)
63
How to solve
Strategy Introduce a Variable

Tool #4 (Introduce a Variable): the fraction 2/3 already forces team A's total to be a multiple of 3, so naming that total 3k makes both of A's numbers whole automatically — 2k wins and k losses, with no fractions to carry. Tool #13 (Convert to Algebra): once A's record is in terms of k, the two "7 more" facts hand over B's whole record for free, and B's win fraction 5/8 becomes one equation in one unknown. Tool #3 (Eliminate Possibilities): kept in reserve as a check — the five choices can be screened by divisibility alone.

1STEP 1

Name the first team's record

Make the games a multiple of three.

A: total = 3k, wins = 2k, losses = k
2STEP 2

Write the second team's record

Write the second record with the same letter.

B: wins = 2k + 7, losses = k + 7, total = 3k + 14
3STEP 3

Build the equation

The second team's win rate gives the equation.

(2k + 7)/(3k + 14) = 5/8
4STEP 4

Solve the equation

Tidying fixes the letter.

8(2k + 7) = 5(3k + 14) → 16k + 56 = 15k + 70 → k = 14
5STEP 5

Find the games played

Converting back gives 42 games.

A's games = 3k = 3 · 14 = 42 → (C)
Answer
42
Rebuild both records from scratch. Team A: 42 games, 28 wins, 14 losses, and 28/42 = 2/3. Team B: 35 wins and 21 losses, for 56 games, and 35/56 = 5/8. Compare: 35 - 28 = 7 more wins and 21 - 14 = 7 more losses, exactly as stated. Every number is a whole number, so the answer holds up.
💡Key takeaway

When a problem says a team won 2/3 of its games, name the total 3k instead of n — the fraction turns into whole numbers on its own, and the rest of the problem becomes one short equation.