AMC 10 · 2022 · #22

Grade 11 algebrageometry-2d
complex-numbersvieta-formulasarea-trapezoidam-gm-inequalityquadratic-equations convert-to-algebraidentify-subproblemsoptimization ↑ Prerequisites: complex-numbersvieta-formulas
📏 Long solution 💡 3 insights
Problem
A real number makes a quadratic have two complex roots. Those two roots and their two reciprocals form the corners of a convex quadrilateral in the complex plane. Among all values giving a genuine quadrilateral, find the one maximizing the area, then say which listed number it is nearest to.

Pick an answer.

(A)
4.5
(B)
5
(C)
5.5
(D)
6
(E)
6.5
How to solve
Strategy Introduce a Variable

The equation hides the roots, so name them. Writing the roots as a + bi and a - bi turns every one of the four vertices into a pair of plain coordinates, and Vieta turns the coefficients into two clean equations in a and b. Once the picture is coordinates, the area becomes a single product ab under the fixed budget a² + b² = 10, and that is a standard maximum.

1STEP 1

The roots must be non-real

The discriminant must be negative.

c² - 4(10) < 0 → c² < 40
2STEP 2

Name the roots

The two roots are conjugates.

z₁ = a+bi, z₂ = a-bi, c = 2a, a² + b² = 10
3STEP 3

Compute the reciprocals

The reciprocals shrink toward the origin.

1/z₁ = (a-bi)/10, 1/z₂ = (a+bi)/10
4STEP 4

Identify the shape

The four points form an isosceles trapezoid.

(a, b), (a, -b), (a/10, b/10), (a/10, -b/10)
5STEP 5

Write the area

The area is proportional to one product.

[Q] = 1/2(2b + b/5)·9a/10 = 1/2·11b/5·9a/10 = 99/100 ab
6STEP 6

Maximize it

The product peaks when the two are equal.

(a-b)² ≥ 0 → ab ≤ (a²+b²)/2 = 5, equality at a=b
7STEP 7

Read off the value

The nearest listed value is 4.5.

a = b = √(5) → c = 2√(5) = √(20) ≈ 4.472
Answer
4.5
Test the winning configuration directly. With a = b = √(5) the roots are √(5) ± √(5) i; their sum is 2√(5) = c and their product is 5 + 5 = 10, matching the equation. The bases are 2√(5) and √(5)/5, the height is 9√(5)/10, and the trapezoid area comes out to 99/20 = 4.95, agreeing with the formula 99/100ab. The answer also has to obey |c| < √(40) ≈ 6.32 from step 1, and 4.472 comfortably does; a choice like 6.5 would have been outside the legal range entirely, so the answer landing in the low part of the list is expected.
💡Key takeaway

Conjugate roots make the four points mirror twins, the shape is forced to be a trapezoid whose area is just a constant times ab, and with a² + b² fixed that product is biggest when a = b.

  • The roots must be non-real
  • Name the roots a ± bi
  • Reciprocals shrink toward the origin
  • Plot: an isosceles trapezoid
  • Area is a multiple of ab
  • Maximize ab under a² + b² = 10
  • Read off c