AMC 10 · 2023 · #13

Grade 8 geometry-3d
space-diagonal-formulasystems-of-equationssurface-areavolume-rectangular-prismvieta-formulas identify-subproblemsconvert-to-algebra ↑ Prerequisites: systems-of-equationssurface-area
📏 Medium solution 💡 2 insights
Problem
A rectangular box has three distinct edge lengths. Its total edge length, its surface area, and its volume are all given. Find the length of the longest interior diagonal.

Pick an answer.

(A)
2
(B)
$\frac{3}{8}$
(C)
$\frac{9}{8}$
(D)
$\frac{9}{4}$
(E)
$\frac{3}{2}$
How to solve
Strategy Identify Subproblems

We never need the individual edges — only the symmetric sums s₁=a+b+c and s₂=ab+bc+ca. Tool #7 (Identify Subproblems) chops the job into three rungs: (a) read off s₁ and s₂ from the given totals, (b) plug into the identity (s₁)² = a²+b²+c² + 2s₂ to get a²+b²+c², (c) take the square root via the Pythagorean-theorem extension to find the space diagonal. Tool #13 (Convert to Algebra) handles the identity; Tool #8 (Analyze the Units) confirms the answer is a length (not an area or volume).

1STEP 1

Read the sum and the pairwise sum

Two conditions give the sum and pairwise sum.

a+b+c=13/4, 2(ab+bc+ca)=11/2
2STEP 2

Find the sum of squares

The volume is not needed.

a²+b²+c² = (a+b+c)² - 2(ab+bc+ca) = (13/4)² - 11/2 = 169/16 - 88/16 = 81/16
3STEP 3

Take the diagonal

The square root gives nine quarters.

d = √(81/16) = 9/4 → (D) 9/4
4STEP 4

Check the units

Squares of lengths added, so the units check out.

[length]² - [length]² = [length]², √([length]²) = [length]
Answer
9/4
Sanity-check the magnitudes: a+b+c = 3.25 and a typical edge is ∼ 1, so the diagonal √(a²+b²+c²) should be a bit bigger than any single edge but smaller than a+b+c. The answer 9/4=2.25 comfortably fits between ∼ 1 and 3.25. Also, (9/4)² = 81/16 matches our intermediate value exactly. The volume abc=1/2 was never used — which is fine, because the diagonal is determined by s₁ and s₂ alone.
💡Key takeaway

You never need the individual edges a,b,c: the totals give a+b+c=13/4 and 2(ab+bc+ca)=11/2, and the identity (a+b+c)² = a²+b²+c² + 2(ab+bc+ca) delivers a²+b²+c² = 81/16. The space diagonal is √(81/16) = (D) 9/4 — and the volume was a red herring.