AMC 10 · 2024 · #21

Grade 11 geometry-2dnumber-theory
tangent-addition-formulatrigonometric-ratiosinteger-pythagorean-triplescomplementary-angles convert-to-algebrawork-backwardsidentify-subproblems ↑ Prerequisites: trigonometric-ratiospythagorean-theoremgcd
📏 Long solution 💡 4 insights
Problem
Three different right triangles each have side lengths forming a primitive Pythagorean triple. The smallest angle of each is taken, and those three angles add to 90°. Two of the triangles are 3-4-5 and 5-12-13. Find the perimeter of the third triangle.

Pick an answer.

(A)
40
(B)
126
(C)
154
(D)
176
(E)
208
How to solve
Strategy Convert to Algebra

An equation about angles is useless on its own — α + β + γ = 90° cannot be solved by staring at it, because the two known angles are ugly numbers like 36.87° that no triple hands over exactly. The move is to stop working with the angles and work with their tangents instead (Convert to Algebra): in a right triangle the tangent of the smallest angle is just short leg over long leg, a clean fraction the triple gives for free. The tangent addition formula turns the angle sum into arithmetic on fractions, and the 90° total is the lucky part — a complementary angle flips tangent into its reciprocal (Work Backwards from the total). That pins the third triangle's leg ratio exactly. Naming the scale factor (Introduce a Variable) and demanding primitivity then forces the actual side lengths, after which the hypotenuse and perimeter are small separate computations (Identify Subproblems), with the answer list available as a final cross-check (Eliminate Possibilities).

1STEP 1

Turn each triangle into a tangent

The tangents are three quarters and five twelfths.

tanα = 3/4, tanβ = 5/12
2STEP 2

Read the sum as a complement

The third is the complement of the first two.

γ = 90° - (α + β)
3STEP 3

Add the two known angles

The formula gives 56 over 33.

tan(α+β) = (tanα + tanβ)/(1 - tanαtanβ) = 7/6/11/16 = 7/6·16/11 = 56/33
4STEP 4

Flip for the complementary angle

Flipping gives 33 over 56.

tanγ = tan(90° - (α+β)) = 1/(tan(α+β)) = 33/56
5STEP 5

Primitive forces the scale to be one

They are coprime, so the scale is 1.

legs = 33k, 56k with gcd(33,56)=1 ⟹ k=1
6STEP 6

Find the hypotenuse

The hypotenuse is 65.

33² + 56² = 1089 + 3136 = 4225 = 65², 33 < 56 < 65
7STEP 7

Add the sides

33 plus 56 plus 65 is 154.

33 + 56 + 65 = 154
Answer
154
Check the three angles numerically. The smallest angle of 3-4-5 is arctan3/4 ≈ 36.870°, of 5-12-13 is arctan5/12 ≈ 22.620°, and of 33-56-65 is arctan33/56 ≈ 30.510°. They total 90.000°, exactly as required. The triple is genuinely right-angled (1089 + 3136 = 4225 = 65²) and genuinely primitive (3 · 11, 2³ · 7, 5 · 13 share nothing). Running the same check on the distractors confirms they fail: 8-15-17 gives a total of about 87.56°, 28-45-53 about 91.38°, 48-55-73 about 100.60°, and 39-80-89 about 85.48°. Only 154 lands on the nose. The size is also sensible: the leftover angle 30.5° is bigger than the 22.6° of 5-12-13 but smaller than the 36.9° of 3-4-5, so the third triangle should be moderately elongated, and 33-56-65 is exactly that.
💡Key takeaway

Angles that add to a right angle are hard to handle directly, but their tangents are exact fractions the triples hand you — add the tangents with one formula, flip the result because the leftover angle is complementary, and the ratio you get is the third triangle itself.

  • Turn each triangle into a tangent
  • Read the sum as a complement
  • Add the two known angles
  • Flip for the complementary angle
  • Primitive forces the scale to be one
  • Find the hypotenuse
  • Add the sides