AMC 8 · 1999 · #14
Grade 8 geometry-2d
Pick an answer.
AMC 8 1999 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The trapezoid's slanted sides are unknown but its height 3 and the two parallel sides 8 and 16 are given. Tool #1 (Draw a Diagram) suggests adding the standard auxiliary lines: drop perpendiculars from B and C down to the bottom base AD. That cut splits the figure into a central rectangle and two congruent right triangles (congruent because the trapezoid is isosceles), which is Tool #7 (Identify Subproblems) — the trapezoid problem becomes a Pythagorean-theorem problem on one easy right triangle.
Drop perpendiculars from B and C to base AD at E and F: the middle BCFE is a rectangle and the two ends are right triangles.
Grade 6 "decompose a polygon into simpler shapes": a rectangle plus two right triangles is far easier to measure than the trapezoid itself.
6.G.A.1Draw A DiagramThe base AD = 16 splits into AE + EF + FD with EF = 8, so the two overhangs satisfy AE + FD = 8.
Splitting the long base into the rectangle's footprint plus two overhangs is the natural Grade 6 length-arithmetic move.
6.G.A.1Identify SubproblemsIsosceles symmetry makes the two triangles congruent, so AE = FD; halving the leftover 8 gives AE = FD = 4.
Grade 4 classifies trapezoids and recognizes that the isosceles version has a vertical line of symmetry — that symmetry forces the two overhangs to match.
4.G.A.2Draw A DiagramTriangle ABE has legs AE = 4 and BE = 3, so the Pythagorean theorem gives the slant AB = 5 (a 3-4-5 triangle).
This is the classic 3-4-5 right triangle from Grade 8 Pythagorean practice — no calculator needed.
8.G.B.7Identify SubproblemsThe other triangle is congruent, so CD = AB = 5, and the four sides sum to 5 + 8 + 5 + 16 = 34.
Grade 4 "perimeter = sum of side lengths" closes the problem once all four sides are known.
4.MD.A.3Identify SubproblemsDrop two height lines, split the trapezoid into a rectangle plus two matching right triangles, and a single Pythagorean step on a 3-4-5 triangle gives slant = 5 — perimeter 5 + 8 + 5 + 16 = 34, answer (D).