AMC 8 · 2001 · #4

Grade 4 number-theoryarithmetic
place-valuedigit-constraintsparitysystematic-enumeration systematic-enumerationcaseworkdigit-constraints ↑ Prerequisites: place-valueparity
📏 Short solution 💡 2 insights
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Problem
Use each of the digits 1, 2, 3, 4, 9 exactly once to build the smallest possible 5-digit even number. What digit ends up in the tens place?

Pick an answer.

(A)
1
(B)
2
(C)
3
(D)
4
(E)
9

AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Guess and Check

Tool #5 (Look for a Pattern) gives the place-value rule: in a multi-digit number, the leftmost place matters most, so to keep the number small we should put the smallest available digit on the left first, then the next smallest, and so on. Tool #6 (Guess and Check) handles the twist — the even-number rule forces the units digit to be 2 or 4, so the greedy left-to-right plan can run into a conflict when it reaches the last two places. When that happens, we swap the units digit and try again.

1STEP 1

Greedy left-to-right: place the smallest available digit first, which gives 12349.

first guess = 12349
2STEP 2

12349 ends in an odd digit, so it fails — an even number needs its units digit to be 2 or 4.

12349 ends in 9 → odd → not allowed
3STEP 3

Put the larger even digit 4 in the units place and fill the rest smallest-first, giving 12394.

1_ten-th 2_th 3_hun 9_tens 4_units = 12394
4STEP 4

The tens digit of 12394 is the second digit from the right: 9.

12394 → tens digit = 9 → (E)
Answer
9
Compare against the other legal candidate. If we had put 2 in the units place instead, the remaining digits 1, 3, 4, 9 filled left-to-right give 13492. Since 12394 < 13492, the choice of 4 in the units place was correct. Also check 12394 uses each of 1, 2, 3, 4, 9 exactly once (yes) and ends in 4 (even, yes). Finally, the tens digit is the second from the right: 1 2 3 9 4 → 9, matching answer (E).
💡Key takeaway

To shrink a number, push the smallest digits to the leftmost places — but if a rule like "must be even" claims a spot, give that spot the larger acceptable digit so the smaller ones can do more work on the left.