Competition · AMC preparation · step 4 of 4
AMC 8 · 2001 · #6
Grade 4 arithmeticpatternPick an answer.
AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The trap is counting trees instead of the spaces between them — the classic "fence-post" mistake. Tool #1 (Draw a Picture) clears that up: sketch six dots in a row and mark the gaps, and you can see at a glance that going from tree 1 to tree 4 crosses 3 gaps, not 4. Tool #7 (Break Into Subproblems) then splits the work into two clean steps: (a) use the 60 feet to find one gap length, (b) multiply by the number of gaps from tree 1 to tree 6.
Count the gaps between trees
Sketch six dots ● ● ● ● ● ●: tree 1 to tree 4 crosses gaps 1-2, 2-3, 3-4, so there are 3 gaps, not 4 (in general b − a).
The Grade 4 "interpret a word problem" move: read carefully and notice 4 - 1 = 3 gaps, not 4.
4.OA.A.3Draw A DiagramFind one gap length
Split the 60 feet evenly among the 3 gaps: each gap is 60 ÷ 3 = 20 feet.
Splitting 60 feet equally into 3 gaps is Grade 3 equal-sharing division.
3.OA.A.3Identify SubproblemsMultiply gaps by gap length
Tree 1 to tree 6 spans 6 − 1 = 5 gaps, each 20 feet, so the distance is 5 × 20 = 100 feet → (B).
Five equal jumps of 20 feet is Grade 3 "equal groups" multiplication.
The distance from the first tree to the last tree equals five gap-lengths.
▸ Why?
The straight run from the first tree to the last is exactly the neighboring-tree gaps laid end to end, with no stretch skipped and none counted twice, so its length is those gap-lengths added back together.
▸ Why?
There are five such gaps: matching each gap to the tree at its far end pairs the gaps one-for-one with the second, third, fourth, fifth, and sixth trees, and that is five trees.
▸ Why?
Since the trees are equally spaced, all of these gaps are the same length, so adding one gap-length five times is just five equal groups of that one length.
When things are lined up evenly, count the spaces between them, not the things themselves. Three spaces give 60 feet, so one space is 20 feet — and five spaces from tree 1 to tree 6 is 5 × 20 = 100 feet, answer (B).
- Count the gaps between trees
- Find one gap length
- Multiply gaps by gap length
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