Competition · AMC preparation · step 4 of 4
AMC 8 · 2002 · #14
Grade 7 rate-ratioPick an answer.
AMC 8 2002 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The original price is never given, so Tool #4 (Introduce a Variable) — let the original price be P — turns the abstract "percent of percent" question into clean arithmetic in P. Tool #7 (Identify Subproblems) splits the chain of discounts into two clear steps: first apply the 30% discount to get the sale price, then apply the 20% discount to that sale price. Comparing the final price to P at the end gives the total percent off.
Name the original price
Let the original price be P, so we can track what fraction of P is left at each step.
Naming the unknown original price is the Tool #4 move and matches the Grade 6 idea of writing an expression with a letter that stands for a number.
6.EE.A.2Introduce A VariableApply the first discount
A 30% discount leaves 70% of the price, so the sale price is 0.7P.
Treating a 30% discount as multiplying by 0.7 is the Grade 6 percent-of-a-quantity move.
6.RP.A.3Identify SubproblemsApply the second discount
Taking 20% off keeps 80% of the sale price, so the final price is 0.7P × 0.8 = 0.56P.
Stacking a second percent discount on an already-discounted price is a Grade 7 multi-step percent-change problem.
Taking another 20% off the already-reduced price 0.7P leaves 0.56P, because the two discounts fold into the single multiplier 0.7 × 0.8.
▸ Why?
A 20%-off charges only the slice of the price it does not remove, and that kept slice is 80% of whatever price it acts on — here the sale price 0.7P — so the final price is 0.8 of 0.7P.
▸ Why?
The sale price splits with no gap or overlap into the 20% slice taken away and the 80% slice still paid, so the amount kept is exactly that 80% slice.
▸ Why?
Taking 80% of the sale price means taking 80 out of every hundred of it, so it equals 80/100 = 0.8 times the sale price — exactly what multiplying by 0.8 does.
▸ Why?
Multiplying 0.8 by (0.7 × P) gives the same result as multiplying (0.8 × 0.7) by P, so the two discount factors regroup into one number 0.7 × 0.8 = 0.56 that scales P.
Compare to the original price
Since 0.56P is 56% of P, the customer paid 56% and saved 44% off the original.
Subtracting the "percent paid" from 100% to get the "percent off" is the standard Grade 7 percent-change wrap-up.
7.RP.A.3Identify SubproblemsStacked discounts multiply, not add — once you write the original price as P, this AMC 8 question is just Grade 7 percent reasoning.
- Name the original price
- Apply the first discount
- Apply the second discount
- Compare to the original price
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