Competition · AMC preparation · step 4 of 4

AMC 8 · 2004 · #16

Grade 5 rate-ratio
fraction-arithmeticfraction-multiplicationratio-proportion identify-subproblems ↑ Prerequisites: fraction-arithmeticmulti-digit-arithmetic
📏 Medium solution 💡 2 insights
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Problem
Two 600 mL pitchers hold orange juice. One is 13\frac{1}{3} full of juice and the other is 25\frac{2}{5} full. Each pitcher is then topped off with water, and both pitchers are emptied into one large container. What fraction of the final mixture is orange juice?

Pick an answer.

(A)
$\frac18$
(B)
$\frac{3}{16}$
(C)
$\frac{11}{30}$
(D)
$\frac{11}{19}$
(E)
$\frac{11}{15}$

AMC 8 2004 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Break into Subproblems

The question asks for one fraction, but to find it we need two separate quantities: how much orange juice is in the container, and how much liquid is in the container in total. Tool #7 (Break into Subproblems) splits the work into those two parallel computations. Tool #4 (Introduce a Variable) is a light support — we treat each pitcher's capacity as the same 600 mL so the two juice amounts can be added directly. Once the two subtotals are in hand, the final fraction is one division and a reduction.

1STEP 1

Find the first pitcher's juice

First pitcher: 13\frac{1}{3} of 600 mL is 200 mL of juice.

OJ₁ = 1/3 × 600 = 200 mL
2STEP 2

Find the second pitcher's juice

Second pitcher: 25\frac{2}{5} of 600 mL is 240 mL of juice.

OJ₂ = 2/5 × 600 = 1200/5 = 240 mL
3STEP 3

Add the two juice amounts

Add both pitchers' juice: 200 + 240 = 440 mL in the container.

OJ_total = 200 + 240 = 440 mL
4STEP 4

Find the total volume

Each pitcher is topped off, so the container holds 600 + 600 = 1200 mL of liquid.

V_total = 600 + 600 = 1200 mL
5STEP 5

Form and simplify the fraction

Juice over total: 4401200\frac{440}{1200} reduces to 1130\frac{11}{30} → (C).

OJ_total/V_total = 440/1200 = 44/120 = 11/30 → (C)
Answer
11/30
Bounds check: each pitcher alone is less than half juice (13\frac{1}{3} and 25\frac{2}{5} are both under 12\frac{1}{2}), so the combined mixture must also be under 12\frac{1}{2}. Our answer 1130\frac{11}{30} ≈ 0.367 sits between 13\frac{1}{3} and 25\frac{2}{5}, exactly where the average of two equal-size pitchers should land. Choices (D) 1119\frac{11}{19} ≈ 0.58 and (E) 1115\frac{11}{15} ≈ 0.73 are both above 12\frac{1}{2}, so they are immediately out.
💡Key takeaway

Solve two small questions first — how much juice, how much liquid in all — then put one over the other and simplify.

  • Find the first pitcher's juice
  • Find the second pitcher's juice
  • Add the two juice amounts
  • Find the total volume
  • Form and simplify the fraction

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