Competition · AMC preparation · step 4 of 4
AMC 8 · 2005 · #2
Grade 6 arithmeticPick an answer.
AMC 8 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question splits cleanly into two small jobs (Tool #7, Identify Subproblems): first find the original total cost of all 5 folders, then take 20% of that total to get the savings. Tool #16 (Change Focus) gives a faster shortcut: since 20% = 1/5, taking 20% of "5 folders" is the same as the cost of 1 folder. Both routes land on the same answer; the subproblem route confirms it with a direct calculation.
Find the total cost
First subproblem: multiply the 5 folders by the price of each to get the original total, $12.50.
Multiplying a count by a per-item price is the Grade 5 decimal multiplication move.
5.NBT.B.7Identify SubproblemsTake 20 percent
Second subproblem: the savings is 20% of that total — one fifth of $12.50, which is $2.50 (C).
"Percent of a quantity" is the Grade 6 percent-as-rate-per-100 calculation: 20% of 12.50.
The money Karl saves equals 20% of the original total cost, and 20% of the total is the same share as one-fifth of it.
▸ Why?
A '20% off' sale takes 20% of the original total off the price, and the money saved is exactly that removed part.
▸ Why?
The original total splits with no gap or overlap into the part Karl still pays and the part the discount takes away, so the part taken away is precisely what he saves.
▸ Why?
Twenty percent of the total means 20 out of every hundred of it — that is 20/100 of the total — and 20/100 names the very same share as one-fifth.
▸ Why?
'20 percent' means 20 for every hundred, so taking 20% of the total is taking 20/100 of it.
▸ Why?
Dividing both the top and bottom of 20/100 by 20 leaves its value unchanged and rewrites the same share as 1/5.
20% off five folders is the same as one folder free — that shortcut turns this AMC 8 problem into a Grade 6 percent-of-a-quantity exercise.
- Find the total cost
- Take 20 percent
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