Competition · AMC preparation · step 4 of 4

AMC 8 · 2005 · #2

Grade 6 arithmetic
percentagemulti-digit-arithmeticfraction-multiplication identify-subproblems ↑ Prerequisites: multi-digit-arithmeticpercentage
📏 Short solution 💡 2 insights
Problem
Karl bought 5 folders at $2.50 each. The next day, the store had a 20%-off sale. How much money could Karl have saved by waiting one day?

Pick an answer.

(A)
$\textdollar 1.00$
(B)
$\textdollar 2.00$
(C)
$\textdollar 2.50$
(D)
$\textdollar 2.75$
(E)
$\textdollar 5.00$

AMC 8 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Identify Subproblems

The question splits cleanly into two small jobs (Tool #7, Identify Subproblems): first find the original total cost of all 5 folders, then take 20% of that total to get the savings. Tool #16 (Change Focus) gives a faster shortcut: since 20% = 1/5, taking 20% of "5 folders" is the same as the cost of 1 folder. Both routes land on the same answer; the subproblem route confirms it with a direct calculation.

1STEP 1

Find the total cost

First subproblem: multiply the 5 folders by the price of each to get the original total, $12.50.

Total cost = 5 × 2.50=2.50 =12.50
2STEP 2

Take 20 percent

Second subproblem: the savings is 20% of that total — one fifth of $12.50, which is $2.50 (C).

Savings = 20% × 12.50=1/5×12.50 = 1/5 ×12.50 = $2.50 → (C)
Answer
$ 2.50
Quick sanity check: 20% of $10 would be $2, so 20% of a number a bit bigger than $10 should be a bit bigger than $2. The answer $2.50 fits, and it sits between (B) $2.00 and (D) $2.75 in the right place. The two extreme choices fail: (A) $1.00 would be only 8% of $12.50, and (E) $5.00 would be 40% — neither matches the 20% discount.
💡Key takeaway

20% off five folders is the same as one folder free — that shortcut turns this AMC 8 problem into a Grade 6 percent-of-a-quantity exercise.

  • Find the total cost
  • Take 20 percent

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