Competition · AMC preparation · step 4 of 4
AMC 8 · 2006 · #3
Grade 6 rate-ratioPick an answer.
AMC 8 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question asks for an improvement in "minutes per lap," but the data is given as totals (laps and minutes mixed together). Tool #8 (Analyze the Units) tells us to convert each pace to the requested unit first — minutes ÷ laps gives minutes per lap. Tool #7 (Identify Subproblems) splits the work into three small steps: find the old per-lap time, find the new per-lap time, and subtract. Each subproblem is a single division or subtraction.
Find the old lap time
Old pace: divide the old minutes by the old laps to get 2.5 min per lap.
Dividing a total by the count gives the per-unit rate — a Grade 6 unit-rate move.
Dividing the total minutes by the total laps gives the number of minutes it takes to swim one lap.
▸ Why?
At a steady pace the 25 minutes is the one-lap time repeated once for each of the 10 laps, so the whole swim is 10 equal groups of that single-lap time.
▸ Why?
Since the total time is the lap count times the one-lap time, dividing the total by the lap count reverses that multiplication and hands back the one-lap time.
Find the new lap time
New pace: the same division gives 2 min per lap.
Same unit-rate formula, new numbers — 24 ÷ 12 = 2 is exact.
6.RP.A.2Analyze The UnitsSubtract the two lap times
Both are in minutes per lap, so subtract old minus new: she shaved off min per lap.
Improvement is old minus new because Elisa got faster, so the old pace is the larger number.
5.NBT.B.7Identify SubproblemsWhen a problem asks "per lap" or "per minute," convert both rates to that unit first — once the units match, subtraction tells the whole story.
- Find the old lap time
- Find the new lap time
- Subtract the two lap times
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