AMC 8 · 2008 · #9
Grade 7 arithmeticPick an answer.
AMC 8 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Two percent changes happen in order, so Tool #7 (Identify Subproblems) splits the problem into two clean steps: first apply the 15% loss, then apply the 20% gain to the result. Tool #3 (Write an Equation) gives the right form for each step — multiply by 0.85 for a 15% loss, multiply by 1.20 for a 20% gain — and then one more equation turns the final dollar amount into a percent change. The trap to avoid is adding -15% and +20% to get +5%; that ignores the fact that the second percent is taken on a smaller base.
A 15% loss keeps 85% of the money, so 85 after Year 1.
"Losing 15%" is the same as "keeping 85%." Multiplying by 0.85 is the Grade 6 way to find a percent of a number.
6.RP.A.3Eliminate PossibilitiesApply the 20% gain to the reduced 100, so 102.
Sequential percent changes use the running balance as the next base. That is why +20% on 17, not $20.
6.RP.A.3Eliminate PossibilitiesThe change is 100 = 2 on the $100 base is a 2% gain → (D).
A Grade 7 percent-change problem: divide the change by the original, then convert to a percent.
7.RP.A.3Identify SubproblemsSequential percent changes do not add up the way they look. A 15% loss then a 20% gain becomes 0.85 × 1.20 = 1.02 — a 2% gain — because the second percent is taken on a smaller amount.