Competition · AMC preparation · step 4 of 4

AMC 8 · 2012 · #2

Grade 4 arithmetic
rateunit-conversionestimation identify-subproblemsdimensional-analysis ↑ Prerequisites: multi-digit-arithmeticrate
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Problem
In East Westmore, a baby is born every 8 hours and one person dies every day. Estimate the yearly population increase, rounded to the nearest hundred.

Pick an answer.

(A)
600
(B)
700
(C)
800
(D)
900
(E)
1000

AMC 8 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Analyze the Units

The rates are in mixed units — births per 8 hours, deaths per day — and the answer wants people per year. Tool #8 (Analyze the Units) lines them up: convert the birth rate into births per day, then per year. Tool #7 (Identify Subproblems) splits the task into three clean pieces — births per day, net change per day, and net change per year — so each step is just one arithmetic move.

1STEP 1

Find births per day

A birth every 8 hours means 24 ÷ 8 = 3 births per day.

(24 hr/day)/(8 hr/birth) = 3 births/day
2STEP 2

Subtract deaths from births

Now both rates are per day, so subtract: 3 - 1 = 2 people per day.

3 births/day - 1 death/day = 2 people/day
3STEP 3

Scale up to one year

Scale the daily gain to a year: 2 × 365 = 730 people per year.

2 people/day × 365 days/year = 730 people/year
4STEP 4

Round to the nearest hundred

The tens digit of 730 is 3, below 5, so 730 rounds down to 700.

730 ≈ 700 → (B)
Answer
700
Three births a day minus one death a day is a net gain of 2 people a day. Two a day for roughly 365 days is about 730, which sits squarely between 700 and 800 but closer to 700. Choice (B) 700 matches; the other choices (600, 800, 900, 1000) are too far from 730 to round there.
💡Key takeaway

This AMC 8 problem only needs Grade 4 skills: convert a rate, subtract, multiply, and round!

  • Find births per day
  • Subtract deaths from births
  • Scale up to one year
  • Round to the nearest hundred

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