AMC 8 · 2015 · #12

Grade 4 geometry-3dcounting
spatial-visualizationcombinations-basicsystematic-enumeration caseworksystematic-enumeration ↑ Prerequisites: combinations-basicspatial-visualization
📏 Short solution 💡 3 insights 📊 Diagram
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Problem
A cube has 12 edges. Count how many unordered pairs of those edges are parallel to each other — pairs like AB and GH, or EH and FG.

Pick an answer.

(A)
6
(B)
12
(C)
18
(D)
24
(E)
36

AMC 8 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Identify Subproblems

Trying to scan all 12 edges and check every pair would mean checking 66 pairs — too many to do safely by eye. Tool #10 (Physical Representation) helps first: pick up any box or cube and look at it. The 12 edges fall into exactly 3 directions (length, width, height), with 4 parallel edges in each direction. Tool #7 (Identify Subproblems) turns the big count into three identical mini-counts: "how many pairs from 4 edges?" Tool #2 (Systematic List) handles each mini-count by listing the pairs in order, so we never double-count or miss one. Add the three mini-counts and we're done.

1STEP 1

Grab any box: a cube's 12 edges point in just 3 directions, 4 per direction, so they split into 3 groups of 4.

12 edges = 3 directions × 4 edges per direction
2STEP 2

Treat one direction at a time: the whole count becomes three copies of the same small question, how many pairs from 4 edges?

total pairs = 3 × (pairs from one group of 4)
3STEP 3

List one group's pairs in order: {1,2},{1,3},{1,4},{2,3},{2,4},{3,4} — that's 6 pairs, with none missed or repeated.

{1,2}, {1,3}, {1,4}, {2,3}, {2,4}, {3,4} → 6 pairs
4STEP 4

The 3 directions each give the same 6 non-overlapping pairs, so the total is 3 × 6 = 18 pairs.

3 × 6 = 18 → (C)
Answer
18
Sanity check by counting differently. The 12 edges form 66 unordered pairs in all (12 × 11 / 2 = 66). Of those, the parallel ones are 18, the perpendicular ones (edges in two different directions) are 3 × (4 × 4) = 48, and 18 + 48 = 66. The bookkeeping closes, so 18 is consistent. Also: 18 sits squarely between the small answers (6, 12) and the inflated traps (24, 36). Choice (D) 24 is what you get if you accidentally treat (e₁, e₂) and (e₂, e₁) as different pairs in 2 groups; choice (E) 36 does it for all three groups. Choice (A) 6 counts only one group, and (B) 12 confuses pairs with edges.
💡Key takeaway

Pick up a box and look at its edges — they only point in 3 directions, so the cube problem is really just "6 pairs, three times" — pure Grade 3 multiplication!