Competition · AMC preparation · step 4 of 4
AMC 8 · 2023 · #15
Grade 6 rate-ratio
Pick an answer.
AMC 8 2023 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is a classic rate problem: speed = distance / time, with the catch that distance is in "blocks" and time is in minutes, but the answer wants miles per hour. Tool #8 (Analyze the Units) keeps the bookkeeping honest: convert blocks to miles (1 block = 0.05 mile) and minutes to hours (5 min = 1/12 hr) before dividing. Tool #7 (Identify Subproblems) splits the journey into two clean pieces — the 5 pre-detour blocks (uses up some time) and the new post-detour leg (the 3-block detour plus the remaining 4 original blocks) — so we can find the remaining time and remaining distance separately.
Find the total time budget
The usual walk is 10 blocks at 1 minute each, so the whole trip must fit inside 10 minutes.
Multiplying blocks by minutes-per-block cancels "blocks" and leaves "minutes" — a Grade 4 distance/time word-problem skill.
4.MD.A.2Analyze The UnitsSubtract the time used
The first 5 blocks used 5 of the 10 minutes, so only 5 minutes remain to reach school from the detour.
Splitting the journey into "already walked" and "still to walk" is the Tool #7 subproblems move.
4.MD.A.2Identify SubproblemsFind the remaining distance
The detour swaps 1 block for 3, so 7 blocks remain; at 0.05 mile each that is 0.35 mile.
Multiplying 7 by the decimal 0.05 is a Grade 5 "decimals to hundredths" calculation.
5.NBT.B.7Analyze The UnitsConvert minutes to hours
Convert the 5 minutes to hours so the answer lands in mph: = hour.
Converting minutes into hours within the same time system is exactly the Grade 5 "convert standard measurement units" standard.
5.MD.A.1Analyze The UnitsDivide distance by time
Divide 0.35 mile by hour (same as × 12): speed = 4.2 mph → (B).
Computing a unit rate (miles per hour) from a distance and a time is Grade 6 rate reasoning.
From the moment the detour begins, the walking speed that still reaches school on time is the leftover distance divided by the leftover time, written in miles per hour.
▸ Why?
Arriving at the usual time means covering exactly the remaining distance in exactly the remaining time, and at a steady pace the only speed that does this is that distance divided by that time.
▸ Why?
For that division to come out in miles per hour, the distance is counted in miles and the time in hours, so the leftover minutes are first renamed as a fraction of an hour.
This AMC 8 problem only needs Grade 6 rate reasoning — distance divided by time — that you already know!
- Find the total time budget
- Subtract the time used
- Find the remaining distance
- Convert minutes to hours
- Divide distance by time
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