AMC 10 · 2003 · #10
Grade 6 countingPick an answer.
AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
A plate is built slot by slot, and each slot is chosen independently, so tool #7 (Identify Subproblems) says: count the choices for each slot and multiply them to get the total number of plates. Do this once for the old scheme and once for the new. Then tool #16 (Change Focus) reframes "increased by how many times" as a single division — new total over old total — rather than a subtraction. Because the answer choices are all ratios of powers of 26 and 10, tool #3 (Eliminate Possibilities) lets the simplified exponents point straight at the matching choice without any large multiplication.
Count the old plates
Five slots — 26 choices for the letter, 10 for each digit. Multiplying gives 26 · 10⁴ old plates.
Filling independent slots multiplies the choices, so a letter slot and four digit slots give 26 · 10⁴.
Filling independent slots multiplies the choices, one factor per slot.
▸ Why?
Each slot is filled without regard to the others, so every combination occurs exactly once.
▸ Why?
A plate is its symbols sitting in fixed places, so choosing the symbols is choosing the plate.
Count the new plates
Now three letter slots (26 each) and three digit slots (10 each). Multiplying gives 26³ · 10³ new plates.
Three letter slots and three digit slots multiply into 26³ · 10³.
6.EE.A.1Identify SubproblemsTurn "how many times" into a division
"By how many times" asks for new ÷ old, not the difference — so form the single fraction of new over old.
"How many times as many" is always a division of the bigger amount by the smaller.
4.OA.A.2Change Focus Count The ComplementSimplify the ratio
Cancel the shared factors: 26³⁻¹ = 26² stays on top, one spare 10 stays below. The ratio is 26²/10 — choice (C).
Dividing like bases subtracts their counts: the 26s drop from 3 to 2 and the 10s from 3 to -1.
6.EE.A.3Eliminate PossibilitiesCount each plate by multiplying the choices in every slot, then divide the new count by the old to see how many times bigger it got.
- Count the old plates
- Count the new plates
- Turn "how many times" into a division
- Simplify the ratio