AMC 10 · 2003 · #14

Grade 8 number-theory
prime-factorizationexponentsgcd casework ↑ Prerequisites: prime-factorizationexponents
📏 Medium solution 💡 2 insights
Problem
The number 3⁸ · 5² is to be written as a single power a^b, where a and b are positive integers. Among all the ways to do this, find the smallest possible value of a + b.

Pick an answer.

(A)
25
(B)
34
(C)
351
(D)
407
(E)
900

AMC 10 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Extreme Principle

The number is already in prime-factored form 3⁸ · 5², so writing it as a^b means pulling the exponent b outside a base a. Tool #4 (Introduce a Variable) pins down what b is allowed to be: b must divide the exponent of every prime, so it can only be a common divisor of 8 and 2. That leaves just two choices for b, and tool #3 (Eliminate Possibilities) checks each. Because a bigger exponent b makes the base a far smaller — and a is what dominates the sum — tool #14 (Extreme Principle) says the smallest a + b comes from pushing b to its largest allowed value. That single idea points straight at the answer.

1STEP 1

See what "a to the b" demands

Writing 3⁸ · 5² = a^b splits each prime's exponent into b equal groups, so b must divide both 8 and 2.

a^b = 3⁸ · 5² → b ∣ 8 and b ∣ 2
2STEP 2

List the only exponents allowed

Since gcd(8, 2) = 2, the common divisors of 8 and 2 are just 1 and 2, so b is 1 or 2 — only two cases.

gcd(8, 2) = 2 → b ∈ {1, 2}
3STEP 3

Take the largest exponent, b = 2

Halving each exponent gives the base a = 3⁴ · 5 = 405, and 405² = 3⁸ · 5² confirms it works.

a = 3⁴ · 5 = 405, 405² = 3⁸ · 5²
4STEP 4

Compare the two cases and pick the smaller sum

b = 2 gives 405 + 2 = 407, while b = 1 gives 164025 + 1 = 164026, so the minimum is 407, choice (D).

b = 2: 405 + 2 = 407; b = 1: 164025 + 1 = 164026 → min = 407 = (D)
Answer
407
Check the winning form directly: 405² = 164025 and 3⁸ · 5² = 6561 · 25 = 164025, so 405² really equals the original number and a + b = 407. The only other legal form, b = 1, gives a + b = 164026, far bigger, so 407 is genuinely the minimum. Choices (A) 25, (B) 34, and (C) 351 are all below 407, but none corresponds to a legal a^b: no valid split of the exponents produces a base and exponent summing to those, since b can only be 1 or 2. So 407 stands.
💡Key takeaway

To pack a number into a^b with the smallest a + b, use the biggest exponent that divides every prime's power — a larger exponent shrinks the base far more than it adds.

  • See what "a to the b" demands
  • List the only exponents allowed
  • Take the largest exponent, b = 2
  • Compare the two cases and pick the smaller sum