AMC 10 · 2005 · #19

Grade 6 arithmetic
mean-median-mode-rangeweighted-averagepercentage easier-related-problemidentify-subproblems ↑ Prerequisites: mean-median-mode-rangepercentage
📏 Medium solution 💡 2 insights
Problem
On a math exam, 10% of the students scored 70, 25% scored 80, 20% scored 85, 15% scored 90, and everyone else scored 95. Find the difference between the mean score and the median score.

Pick an answer.

(A)
0
(B)
1
(C)
2
(D)
4
(E)
5

AMC 10 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Solve an Easier Related Problem

The problem gives percentages but no head count, so Tool #9 (Solve an Easier Related Problem) pins the count at a convenient 100 students; then every percentage becomes a plain number of students and the abstract question turns into counting real scores. Tool #7 (Identify Subproblems) splits the work into two independent pieces — find the median, find the mean — and only at the end subtracts them. Tool #3 (Eliminate Possibilities) uses the multiple-choice frame as a safety net: the difference is a small whole number, so a quick estimate can rule out the far-apart choices.

1STEP 1

Turn percents into student counts

The four listed groups total 70%, so the remaining 30% scored 95; take 100 students and each percent becomes a head count.

100-(10+25+20+15)=30% scored 95; 10, 25, 20, 15, 30 students
2STEP 2

Locate the median

Lined up in order, positions 1–35 hold the 70s and 80s and 36–55 hold the 85s, so the 50th and 51st scores are both 85.

70s:1-10, 80s:11-35, 85s:36-55 → 50th=51st=85
3STEP 3

Compute the mean

Weighted total 70(10)+80(25)+85(20)+90(15)+95(30)=8600, so the mean is 8600÷100=86.

(700+2000+1700+1350+2850)/100=8600/100=86
4STEP 4

Subtract to get the difference

Mean 86 minus median 85 gives 1; the two centers nearly coincide, which rules out 2, 4, and 5 — choice (B).

86-85=1 → (B)
Answer
1
The mean 86 and median 85 both sit inside the 80-to-90 range where almost all the scores are packed, so both numbers are believable. The mean edges above the median because the 30% of high 95s pull the average up while the median only cares about the middle position — a right-leaning spread, exactly what a difference of 1 (mean bigger than median) signals. Using 100 students was a free choice: with 20 students the counts 2,5,4,3,6 give the same median 85 and mean 1720÷20=86, so the difference stays 1, confirming it does not depend on the head count.
💡Key takeaway

When only percents are given, pretend there are 100 people so each percent becomes a count; then the median is the middle score in order and the mean is the weighted average.

  • Turn percents into student counts
  • Locate the median
  • Compute the mean
  • Subtract to get the difference