AMC 10 · 2008 · #6
Grade 6 rate-ratioPick an answer.
AMC 10 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Everything here is about positions along one straight segment, which is exactly what Tool #1 (Draw a Diagram) is for. If I mark where B and C fall on AD using fractions of the whole, the answer BC is just the gap between the two marks. Tool #4 (Introduce a Variable) supports this by letting me call the whole length AD one unit, so each ratio condition turns directly into a fraction I can plot.
Call the whole segment 1
Both clues are ratios, so the true length of AD does not matter — set AD = 1 and every length reads off as a fraction of the whole.
Naming the whole "1" makes every piece automatically read out as a fraction of the whole.
6.EE.B.6Introduce A VariableLocate B
AB = 4 · BD is a 4 to 1 split, so AD is 5 equal parts: BD is and measured from A.
A 4:1 split means 5 equal parts, and B lands at the 4-part mark.
A four-to-one split means five equal parts, and the point lands at the four-part mark.
▸ Why?
The two pieces together make the whole, so a ratio names how many equal shares each piece takes.
▸ Why?
A ratio fixes only the relative sizes, so calling the whole one makes each mark read out directly.
Locate C
AC = 9 · CD is a 9 to 1 split, so AD is 10 equal parts: CD is and measured from A.
A 9:1 split means 10 equal parts, and C lands at the 9-part mark.
6.RP.A.3Draw A DiagramMeasure the gap BC
Since is under , the order is A, B, C, D, so the gap BC = AC - AB = — choice (C).
On the diagram BC is simply the distance from B's mark to C's mark.
5.NF.A.1Draw A DiagramTurn each "4 times" or "9 times" clue into equal parts, mark both points on one line, and the middle piece is just the gap between the marks.
- Call the whole segment 1
- Locate B
- Locate C
- Measure the gap BC