AMC 10 · 2009 · #6
Grade 7 geometry-2d
Pick an answer.
AMC 10 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The one fact the picture hides is the semicircle's radius. Reading the figure carefully (Tool #1) unlocks it: the circle stands on the flat edge and its top just reaches the arc, so its full diameter fits between them and equals the semicircle's radius. Once both radii are known, the area question splits into two clean pieces (Tool #7): the semicircle's area and the circle's area. The shaded part is not computed directly but as what is left over after removing the circle (Tool #16), which turns the fraction into a simple subtraction and cancellation.
Read the semicircle's radius from the figure
The center sits 2 above the flat edge and the top 2 more, so the semicircle's radius is 4.
The circle stacks bottom-to-top from the flat edge to the arc, so its diameter is the big radius.
The inner circle stacks from the flat edge to the arc, so its diameter is the big radius.
▸ Why?
Touching from inside puts both centres and the touch point on one line through the big centre.
▸ Why?
The big circle keeps the same distance from its centre everywhere, so that line is exactly one radius long.
Area of the semicircle
A semicircle is half a full circle: radius 4 gives π·4² = 16π, so half of that is 8π.
Use the circle-area formula on radius 4, then take half because only a semicircle is drawn.
7.G.B.4Identify SubproblemsArea of the inscribed circle
The inscribed circle has radius 2, so the same formula gives area 4π.
A radius-2 circle has area 4π straight from π r².
7.G.B.4Identify SubproblemsSubtract, then form the fraction
Shaded is what's left after removing the circle: 8π - 4π = 4π, and 4π over 8π reduces to 1/2.
The circle eats exactly half the semicircle's area, so what is left is the other half.
6.RP.A.3Change Focus Count The ComplementThe circle's diameter equals the semicircle's radius, so the circle covers exactly half the semicircle and the shaded leftover is the other half, 1/2.
- Read the semicircle's radius from the figure
- Area of the semicircle
- Area of the inscribed circle
- Subtract, then form the fraction