AMC 10 · 2010 · #2
Grade 6 rate-ratioPick an answer.
AMC 10 2010 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question stacks a few small tasks: find the second meeting's length, add the two meetings, express the day in the same unit, then turn the ratio into a percent. Tool #7 (Identify Subproblems) keeps each step clean. Tool #8 (Analyze the Units) is the guardrail: the day is in hours and the meetings in minutes, so the one real trap is comparing them before matching units. Convert the day to minutes and the percent falls out.
Double the first meeting
The second meeting is twice the first, so it ran 2 × 45 = 90 minutes.
"Twice as long" just means double it, so the second meeting is two of the first stacked together.
4.OA.A.1Identify SubproblemsAdd the two meetings
Add the two meetings: 45 + 90 = 135 minutes of meeting time.
Total time in meetings is simply the first plus the second, added up.
4.NBT.B.4Identify SubproblemsConvert the day to minutes
Match the units: 1 hour is 60 minutes, so the day is 9 × 60 = 540 minutes.
You can only compare minutes to minutes, so trade the hours in for the minutes they are worth.
5.MD.A.1Analyze The UnitsTurn the ratio into a percent
Part over whole: , which is 25%, so the answer is (C).
Percent is just the part-over-whole fraction rewritten as a piece of 100, and a quarter of anything is 25%.
A percent is just the part-over-whole fraction rewritten as a piece of a hundred.
▸ Why?
A percent counts hundredths, so the fraction has to be measured against a hundred.
▸ Why?
Scaling top and bottom by the same factor leaves a different-looking fraction naming the same amount.
Before you compare two amounts, make sure they are in the same unit — then the percent is just part over whole.
- Double the first meeting
- Add the two meetings
- Convert the day to minutes
- Turn the ratio into a percent