AMC 10 · 2014 · #12
Grade 8 geometry-2d
Pick an answer.
AMC 10 2014 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The shaded region has a jagged, hard-to-measure boundary. Instead of measuring it directly, take the whole hexagon and subtract the pieces that were removed. That turns one messy region into two clean pieces: the hexagon's area and the total sector area.
Reframe as whole minus cut-outs
The sectors are exactly what was removed from inside, so shaded area is the hexagon's area minus the six sectors.
It is easier to measure the full shape and take away the holes than to trace the leftover directly.
7.G.B.6Change Focus Count The ComplementArea of the hexagon
Split it into 6 equilateral triangles of side 6; each has area , so the hexagon is .
A regular hexagon is six identical equilateral triangles fanned around its center.
A regular hexagon is six identical equilateral triangles fanned around its centre.
▸ Why?
The angles around the centre fill a full turn, so six equal wedges are a sixth of it each.
▸ Why?
Two equal radii with that wedge angle force the third side to match, making each wedge equilateral.
Area of the six sectors
Each sector fills a 120-degree interior angle, so it is of a radius-3 circle: each, in all.
A sector is just a slice of a whole circle, sized by its share of 360 degrees.
7.G.B.4Identify SubproblemsSubtract to finish
Take off , leaving — choice (C).
The leftover shaded area is exactly what remains after the round corners are removed.
7.NS.A.3Change Focus Count The ComplementTo find a leftover region with rounded bites taken out, measure the whole shape and subtract the pieces that were cut away.
- Reframe as whole minus cut-outs
- Area of the hexagon
- Area of the six sectors
- Subtract to finish