AMC 10 · 2014 · #6

Grade 6 rate-ratio
fraction-arithmeticratio-proportion identify-subproblems ↑ Prerequisites: fraction-arithmetic
📏 Medium solution 💡 2 insights
Problem
Orvin brings exactly enough money to buy 30 balloons at the regular price. A sale lets him buy one balloon at the regular price and a second balloon at 1/3 off. Using all his money and the deal as often as possible, find the greatest number of balloons he can buy.

Pick an answer.

(A)
33
(B)
34
(C)
36
(D)
38
(E)
39

AMC 10 2014 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Introduce a Variable

No dollar amount is given, so Tool #4 (Introduce a Variable) fixes a convenient regular price; because the count of balloons cannot depend on the price, any handy value works, and 3 makes the 1/3 discount a whole number. Tool #8 (Analyze the Units) tracks dollars per balloon and dollars per pair. Tool #7 (Identify Subproblems) turns the sale into one repeatable unit — a pair of balloons at a fixed cost — so the whole purchase is just 'how many pairs fit in the money.'

1STEP 1

Pick a convenient price

The price never appears in the answer, so let it be 3 dollars: Orvin's money is 30 × 3 = 90 dollars.

money = 30 × 3 = 90 dollars
2STEP 2

Price the discounted balloon

In each pair the second balloon is 1/3 off, a 1 dollar cut, so it costs 3 - 1 = 2 dollars.

1/3 × 3 = 1, 3 - 1 = 2 dollars
3STEP 3

Cost of one pair

Buy two at a time: one full-price balloon plus one discounted one is 3 + 2 = 5 dollars per 2 balloons.

3 + 2 = 5 dollars per 2 balloons
4STEP 4

Fit the pairs into the money

A pair costs 5 dollars and he has 90, so he affords 90 ÷ 5 = 18 pairs with nothing left over.

90 ÷ 5 = 18 pairs
5STEP 5

Count the balloons

Each pair holds 2 balloons, so 18 × 2 = 36 balloons, and the money is spent exactly: choice (C).

18 × 2 = 36 → (C)
Answer
36
Without the sale, 90 dollars buys 30 balloons, so the answer must be more than 30; 36 is a believable bump. Check the saving directly: each pair costs 5 instead of 6, a 1/6 saving, so the money stretches to 30 × 6/5 = 36 balloons. Both routes give 36, and the money is used up exactly, matching choice (C).
💡Key takeaway

Buy balloons two at a time: every second one is a third off, so five dollars' worth of deal gets you six dollars' worth of balloons, stretching money for 30 into 36.

  • Pick a convenient price
  • Price the discounted balloon
  • Cost of one pair
  • Fit the pairs into the money
  • Count the balloons