AMC 10 · 2015 · #4
Grade 6 rate-ratioPick an answer.
AMC 10 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The two "times as many" statements chain together, so Tool #4 (Introduce a Variable) lets one letter for Mia's eggs carry everyone's count: Sofia and Pablo become simple multiples. Tool #6 (Guess and Check) is the shortcut twin here — picking the smallest whole number for Mia keeps every count a whole number and avoids fractions until the very last step. Once the equal share is known, the question "what fraction of his eggs" is a single part-to-whole ratio, and Tool #3 (Eliminate Possibilities) confirms the answer is one of the small fractions offered.
Chain the counts from Mia up
Let Mia = m; then Sofia = 2m and Pablo = 3× 2m = 6m.
Each ratio just multiplies the previous person's pile, so one starting number fixes all three.
6.RP.A.3Use Matrix LogicFind the equal share
The total stays m+2m+6m=9m, so each equal share is 3m eggs.
Equal shares means total divided by three, and the total is untouched by who hands eggs to whom.
6.EE.A.2Use Matrix LogicGive Sofia just enough, then take the fraction
Sofia needs 3m-2m=m more from Pablo's 6m: fraction = 1/6 — choice (B).
Sofia's shortfall is exactly Mia's original pile, and comparing that to Pablo's six piles gives one part in six.
6.RP.A.1Use Matrix LogicName the smallest pile with a letter, build everyone else from it, and the messy ratios turn into easy whole numbers.
- Chain the counts from Mia up
- Find the equal share
- Give Sofia just enough, then take the fraction