AMC 10 · 2016 · #15
Grade 4 geometry-2dPick an answer.
AMC 10 2016 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Trying to actually fill the grid is slow and there are many arrangements. Instead, color the grid like a checkerboard (Tool #1). The chain 1→2→…→9 only steps between edge-sharing squares, which always swap color, so the numbers' even/odd pattern lines up with the colors (Tool #5). Counting how many odd and even numbers there are then forces which color the corners-and-center must be (Tool #3) — and that pins the corner-plus-center total without ever building a full grid.
Color the grid like a checkerboard
Shade the grid like a checkerboard so the five corner-and-center squares are dark and neighbors always differ in color.
On a checkerboard every step to a neighbor flips the color, so corners and center share one color and the edges share the other.
4.OA.C.5Draw A DiagramMatch parity to color
Along the chain 1→2→…→9 each step flips both the color and the number's parity, so every dark square holds one parity.
Two things that both flip at every single step stay perfectly matched the whole way.
2.OA.C.3Look For A PatternForce the odds onto the five dark squares
Five odds {1,3,5,7,9} but only four evens, so the five dark squares must be the odds, summing to 25.
Five same-parity squares can't be filled by only four evens, so they must be the odds.
2.NBT.B.5Eliminate PossibilitiesSubtract to isolate the center
The five dark squares total 25 and the four corners total 18, so the center is 25 - 18 = 7, choice (C).
Corners and center together are known, and the corners alone are known, so the leftover is the center.
2.NBT.B.5Eliminate PossibilitiesColor the grid like a checkerboard: consecutive numbers must hop to a different color, so the five corner-and-center squares are exactly the five odd numbers — and 25-18 leaves the center.
- Color the grid like a checkerboard
- Match parity to color
- Force the odds onto the five dark squares
- Subtract to isolate the center