AMC 10 · 2017 · #11
Grade 8 geometry-3dPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The whole problem hinges on seeing the shape, so Tool #17 (Visualize Spatial Relationships) comes first: the points within 3 of a straight segment form a tube (cylinder) wrapped around the middle, capped by a rounded dome (hemisphere) at each end. Once the picture is clear, Tool #7 (Identify Subproblems) splits the volume into pieces we already have formulas for — a cylinder plus the two end domes, which together make one full sphere of radius 3. Tool #4 (Introduce a Variable) names the unknown length L, turns the total volume into the equation 9π L + 36π = 216π, and we solve for L.
Picture the solid
Points within 3 of the segment sweep a radius-3 cylinder, and each end adds a radius-3 hemisphere cap — a cylinder plus two caps.
A segment is a line with two ends, so its 3-unit neighborhood is a tube down the middle with a dome sealing each end.
8.G.C.9Visualize Spatial RelationshipsCombine the two caps into a sphere
The two radius-3 hemisphere caps join into one whole radius-3 ball, whose sphere volume ·π·3³ is 36π.
Two matching halves of a ball are just one whole ball, so skip the halves and use the sphere formula once.
Two matching halves of a ball are just one whole ball, so the caps can be handled in a single step.
▸ Why?
Sliding one cap onto the other moves it without stretching it, so the two are the same size.
▸ Why?
The solid is exactly the tube plus the two caps, so their volumes simply add.
Write the cylinder volume with a variable
Let L be AB's length, the cylinder's height; its volume is π·3²·L = 9πL, so the whole solid is 9πL + 36π.
The tube's volume is its circular base times how far it runs, and the length of the segment is exactly that run.
8.G.C.9Introduce A VariableSet the volume equal and solve
Set 9πL + 36π = 216π; dividing by π gives 9L + 36 = 216, so 9L = 180 and L = 20 — answer (D).
Once the cap volume is set aside, the leftover volume is all cylinder, and its length falls straight out of one linear equation.
8.EE.C.7Introduce A VariableEverything within a fixed distance of a segment is a tube with a domed cap on each end — add the cylinder and the two caps (a whole sphere), then solve for the length.
- Picture the solid
- Combine the two caps into a sphere
- Write the cylinder volume with a variable
- Set the volume equal and solve