AMC 10 · 2017 · #7
Grade 8 geometry-2dPick an answer.
AMC 10 2017 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is a paths-on-a-shape problem, so Tool #1 (Draw a Diagram) is the natural start: sketch the square and mark both routes. The two routes split into two independent measurements, so Tool #7 (Identify Subproblems) lets us find Jerry's total and Silvia's total separately. Jerry's total is two sides; Silvia's is the diagonal, which the right triangle inside the square turns into a Pythagorean length. Finally Tool #8 (Analyze the Units) keeps the comparison honest: 'how much shorter' means the gap measured as a percent of Jerry's trip.
Draw it and measure Jerry's route
Only the ratio matters, so let the side be 1; Jerry walks two sides, so his trip is 1+1.
Picking the side to be 1 costs nothing because a percent comparison stays the same at any scale.
6.EE.B.6Draw A DiagramSilvia's route is the diagonal
Silvia's straight line is the square's diagonal—the hypotenuse of a right triangle with legs 1 and 1—so it is √(2).
A square's diagonal closes off a right triangle, so its length is fixed by the two equal legs.
8.G.B.7Identify SubproblemsFind how much shorter the diagonal is
Swap in √(2)≈1.41; the diagonal falls short of Jerry's 2 by the gap 0.59.
An irrational length like √(2) is easiest to compare once you swap in a close decimal.
8.NS.A.2Analyze The UnitsTurn the gap into a percent
Divide the gap by Jerry's total: 0.59/2≈0.29, i.e. 29%—closest to the listed 30%, choice (A).
'Percent shorter' is the saved distance divided by the original distance, not by the new one.
6.RP.A.3Analyze The UnitsCutting straight across a square instead of walking two sides saves you about 30% of the distance, because the diagonal is √2 times one side while two sides total 2.
- Draw it and measure Jerry's route
- Silvia's route is the diagonal
- Find how much shorter the diagonal is
- Turn the gap into a percent