AMC 10 · 2020 · #7
Grade 6 geometry-2dPick an answer.
AMC 10 2020 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Two clean subproblems hide inside this magic-square question. Sub-A: find the grand total of all 25 numbers. Sub-B: each row sums to the same C, and 5 rows partition the grid, so grand total = 5C. Tool #7 surfaces those two pieces. Tool #9 (easier related) lets us pair -10 with 10, -9 with 9, etc., to compute the total in one mental step instead of summing 25 values directly. Tool #3 pins the answer down to one of the five choices.
Pair each number with its negative: -10 through 10 cancels to 0, leaving only 11, 12, 13, 14.
Symmetric pairs around 0 cancel — fastest way to sum a balanced range.
6.NS.C.5Solve An Easier Related ProblemAdd the leftover four positives: they total 50.
Pair 11+14 = 25 and 12+13 = 25, then 25+25 = 50.
4.NBT.B.4Solve An Easier Related ProblemThe 25 numbers total 50; the 5 rows tile the grid, so the five row sums add to that total: 5C = 50.
Five equal slices that fill the whole grid must each be one-fifth of the total.
3.OA.A.3Identify SubproblemsDivide both sides by 5: C = 10.
Divide both sides by 5.
3.OA.A.3Identify SubproblemsC = 10 is choice (C); the column and diagonal rules only constrain the layout, never the common sum.
Read the matching choice; extra symmetry conditions don't change C.
4.NBT.A.2Eliminate PossibilitiesThis AMC 10 problem only needs Grade 6 'negatives cancel positives' plus dividing into equal groups — the 25 numbers add to 50, the 5 row sums all equal the same number C, so 5C = 50 gives C = 10.