AMC 10 · 2021 · #4
Grade 6 rate-ratioPick an answer.
AMC 10 2021 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #5 (Pattern) spots the steady +7 jumps and the equal-spaced list. Tool #9 (Easier Problem) checks the idea on a tiny version — pair 5 and 208, 12 and 201, …, each pair sums to 213. Tool #7 (Subproblems) then splits the work into two pieces: "what is the last-second distance?" and "how many pairs, each 213?".
List the first few: 5, then 5 + 7 = 12, then 19, 26 — each second adds the same 7, a steady ladder.
Listing the first few terms makes the pattern visible — Grade 5 "generate a numerical pattern from a rule".
5.OA.B.3Look For A PatternFrom the 1st second to the 30th the +7 jump happens 29 times, so the last second is 5 + 29 × 7 = 208 inches.
Counting how many 7-jumps separate the first and last term — Grade 5 "write expressions that record calculations".
5.OA.A.2Identify SubproblemsPair first with last, second with second-to-last: each pair sums to 5 + 208 = 213, and 30 terms make exactly 15 pairs.
When two numbers walk toward each other at the same pace, their sum stays constant — Grade 5 "identify relationships between two patterns".
5.OA.B.3Solve An Easier Related ProblemAdd all 15 pair sums: 15 × 213 = 3,195 inches — choice (D).
Multiplying a two-digit and a three-digit number — Grade 5 "fluently multiply multi-digit whole numbers".
5.NBT.B.5Identify SubproblemsThis AMC 10 problem only needs Grade 6 "average × count = total" — pair the first second (5) with the last (208), every pair sums to 213, and 15 pairs give 3,195 inches.