AMC 10 · 2025 · #4
Grade 8 number-theoryPick an answer.
AMC 10 2025 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The digits a and b are the unknowns, so Tool #4 (Introduce a Variable) names them and turns the place-value meaning of each numeral into an equation. Solving that equation only pins down the ratio of the digits, so Tool #6 (Guess and Check) tests the small digit pairs that fit, and Tool #3 (Eliminate Possibilities) uses the base-seven digit limit (a,b ≤ 6) to throw out the larger pair that also fits the ratio but is an illegal digit.
Write each numeral by place value
Place value makes the left digit worth one base each: 7a+b in base seven, and 9b+a for the reversed numeral in base nine.
A two-digit number is just the base times the first digit plus the second digit.
A two-digit numeral is the base times its first digit plus its second.
▸ Why?
A numeral is its digits weighted by their places, so each place carries its own weight.
▸ Why?
Those weights climb by using the base one more time at each step.
Set the values equal and simplify
Equating them gives 7a+b=9b+a; gathering like terms leaves 6a=8b, and halving both sides reaches 3a=4b.
Move like terms across the equals sign to shrink the relationship down to its simplest form.
8.EE.C.7Introduce A VariableFind the digits and add
So a:b=4:3; the next pair (8,6) breaks the base-seven digit limit, leaving a=4, b=3 and a+b=7.
A ratio fixes the digits up to scaling, and the digit limit keeps only the smallest valid scale.
6.RP.A.1Eliminate PossibilitiesA two-digit number in any base is just the base times the first digit plus the second digit, so writing that out turns a base puzzle into a simple equation.
- Write each numeral by place value
- Set the values equal and simplify
- Find the digits and add